Answer 1 / 25
Step-by-step explanation:
The probability that the first
of the three mutants will take over the population = 2 / 100
The probability that the second
of the three mutants will take over the population = 1.01 / 100
The probability that the third
of the three mutants will take over the population = 0.99 / 100
Therefore, the probability that each of the three mutants will take over the population = probability of the first,second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99)/100 = 4 / 100 = 2/25
The 2nd one is the answer because it shows Distributive Property which is a(b+c) or <span>(b+c)a.</span>
Answer:
-4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
4x + 5y = -12
-2x + 3y = -16
<u>Step 2: Rewrite Systems</u>
-2x + 3y = -16
- Multiply everything by 2: -4x + 6y = -32
<u>Step 3: Redefine Systems</u>
4x + 5y = -12
-4x + 6y = -32
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
- Combine 2 equations: 11y = -44
- Divide 17 on both sides: y = -4