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11Alexandr11 [23.1K]
3 years ago
14

Two individuals that are heterozygous for tongue rolling mate. What are the predicted genotypic and phenotypic ratios for this c

ross?
Biology
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

Genotypic ratio = 1:2:1

Phenotypic ratio = 3 tongue rollers : 1 non-tongue roller

Explanation:

This question involves a gene coding for the ability to roll the tongue or not in humans. The allele for tongue rolling (R) is dominant over the allele for non-tongue rolling (r).

According to this question, two individuals that are heterozygous for tongue rolling mate i.e. Rr × Rr. The proportion of offsprings that will be likely produced from this cross will be: RR, Rr, Rr, and rr.

- Offsprings with RR, Rr, Rr are tongue rollers

- Offsprings with 'rr' are non-tongue rollers.

Hence, the predicted genotypic and phenotypic ratio are as follows:

Genotypic ratio = 1 RR :2Rr :1rr

Phenotypic ratio = 3 tongue rollers : 1 non-tongue roller

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In the figure below, ΔMNO≅ΔPQR.What is the measure of ∠P? Show your work and explain your reasoning.
Juliette [100K]

Answer:

\huge\boxed{\sf P = 79.5\°}

Explanation:

<u>Given that:</u>

ΔMNO ≅ ΔPQR

That means

M ↔ P

N ↔ Q

O ↔ R

So,

∠P ≅ ∠M

Given that P = 3x + 20.4 and M = 5x - 19

3x + 20.4 = 5x - 19

Add 19 to both sides

3x + 20.4 + 19 = 5x

3x + 39.4 = 5x

Subtract 3x to both sides

39.4 = 5x - 3x

39.4 = 2x

2x = 39.4

Divide both sides by 2

x = 19.7

<u>Given that:</u>

P = 3x + 20.4

P = 3(19.7) + 20.4            (x = 19.7)

P = 59.1 + 20.4

P = 79.5°

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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2 years ago
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How many high-phosphoryl-transfer-potential molecules are required to synthesize phosphatidylethanolamine from ethanolamine and
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The answer is Three high energy molecules. One molecule of ATP to form phosphorylethanolamine and two molecules of ATP to regenerate CTP from CMP.

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