Answer:

Step-by-step explanation:
Since we're looking at perpendicular lines, the slope of the new line is the reciprocal of the original line.
So the slope of our new line is 
So far, we are looking at 
Now we need to find the b value by plugging in the given point.

So the final equation is 
Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
The answer is 7 because 70 ÷ 10 = 7.
Answer:
9m
Step-by-step explanation:
5 - 3 + 7 = 9
Answer:
Step-by-step explanation: