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3 years ago

Someone please help

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

Answer:

A.) slope is 0, y=2

Step-by-step explanation:

slope = 0 cause its flat

y =2 by the graph

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We have n = 100 many random variables xi 's, where the xi 's are independent and identically distributed bernoulli random variab

Alex777 [14]

Recall that for a random variable $X$ following a Bernoulli distribution $\mathrm{Ber}(p)$ , we have the moment-generating function (MGF)

$M_X(t)=(1-p+pe^t)$

and also recall that the MGF of a sum of i.i.d. random variables is the product of the MGFs of each distribution:

$M_{X_1+\cdots+X_n}(t)=M_{X_1}(t)\times\cdots\times M_{X_n}(t)$

So for a sum of Bernoulli-distributed i.i.d. random variables $X_i$ , we have

$M_{\sum\limits_{i=1}^nX_i}(t)=\displaystyle\prod_{i=1}^n(1-p+pe^t)=(1-p+pe^t)^n$

which is the MGF of the binomial distribution $\mathcal B(n,p)$ . (Indeed, the Bernoulli distribution is identical to the binomial distribution when $n=1$ .)

8 0

3 years ago

Can someone help me with this two problems?

ANEK [815]

2x+4y=0

substitute y with 0

2x+4(0)=0

solve the equation

2x+0=0

2x=0

divide by 2 on both sides

x=0

4x+8y=7

substitute y with 0

4x+8(0)=7

solve the equation

4x+0=7

4x=7

divide by 4 on both sides

x=7/4 or x=1 3/4 or x=1.75

3x-7y=-29

2x+2y=6

solve the bottom equation

3x-7y=-29

x=3-y

substitute for x

3(3-y)-7y=-29

solve the equation

y=19/5

now substitute for y

x=3- $\frac{19}{5}$

solve for x

x=-4/5

the possible solution of the system is the ordered pair

(x,y)=( $-\frac{4}{5} ,\frac{19}{5}$ )

3 0

4 years ago

As the figure shows Elton runs 500 m to point b first then he turns 100 degrees and runs another 350 m to point c how far is the

Alex777 [14]

Answer:

658.24 m

Step-by-step explanation:

Let A be the point from where Elton started. Connect points A and C, you get triangle ABC with AB=500 m, BC=350 m and m∠B=100°. Use the cosine rule to determine the length of the segment AC:

$AC^2=AB^2+BC^2-2\cdot AB\cdot BC\cdot \cos \angle B,\\ \\AC^2=500^2+350^2-2\cdot 500\cdot 350\cdot \cos 100^{\circ},\\ \\AC^2=250000+122500-350000\cdot (-0.174),\\ \\AC^2\approx 433276.8622,\\ \\ AC\approx 658.24\ m.$