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jek_recluse [69]
3 years ago
6

Can someone help me find some equations that represent proportional relationships in the real world and what they represent in t

he real world, I'm stumped.
Mathematics
1 answer:
otez555 [7]3 years ago
7 0
BBB. B to
I B. B. By b oy.
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Suppose we are testing the null hypothesis H 0 mu=20 and the alternative H iu =20 , normal population with sigma=6 A random samp
cupoosta [38]

Answer:

The value of the test statistic is z = -1.5

Step-by-step explanation:

The formula for the test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the statistic, \mu is the mean, \sigma is the standard deviation and n is the number of observations.

In this problem, we have that:

\mu = 20, X = 17, \sigma = 6, n = 9

So

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{17 - 20}{\frac{6}{\sqrt{3}}}

z = -1.5

The value of the test statistic is z = -1.5

8 0
3 years ago
What is the answer please help
satela [25.4K]

0.9 seconds is the correct answer

7 0
3 years ago
If p = the mountain bike's original price in dollars, which algebraic expression
Anna [14]

Answer:

A

Step-by-step explanation:

125 is the amount of discount, so for example if p was 500 and discounted by 125 (p-125), you'd get 375(example of reduced price).

4 0
3 years ago
The length of a side of a square is √7 cm. What is the perimeter of the square? (Perimeter = the distance around the outside of
Sonja [21]
Since the square has 4 sides, you only have to add \sqrt{7} four times.

The <span>perimeter of the square is: </span><span>4 \cdot \sqrt{7} = 10.6 cm </span>
4 0
3 years ago
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The sine of angle θ is 0.3.<br><br> What is cos(θ)?
Sergio [31]

The answer:

\sqrt{9}1 /10

Explanation to your question:

Since the sin of theta is 0.3, we can reasonably deduct that the opposite side to theta has a ration of 3 to 10 to that of the hypotenuse. Thus, the adjacent side to theta, using the pythagorean theorem, will be root91. Therefore, since the cosine of theta is the adjacent/hypotenuse, we get root 91/10

6 0
3 years ago
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