Answer:
30.007
Step-by-step explanation:
Answer:
4989600 ways
Step-by-step explanation:
From the question,
The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)
⇒ n!/(r₁!r₂!r₃!) ways
Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.
Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2
Substitute these value into the expression above
11!/(2!2!2!) = (39916800/8) ways
4989600 ways
Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways
Answer:
9/10
Step-by-step explanation: the magic mushroom said so
Answer:
Option C is correct i.e. 2.
Step-by-step explanation:
Given the function is f(x) = x² +8x -2.
We can compare it with general quadratic expression i.e. ax² +bx +c.
Then a = 1, b = 8, c = -2.
We can find the number of real root by finding discriminant of the equation ax² +bx +c =0 as follows:-
D = b² -4ac
D = 8² -4*1*-2
D = 64 +8
D = 72.
When D is a positive value, then we have two real roots of the equation.
Hence, option C is correct i.e. 2.
