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2 years ago

On a test of 80 problems, Bill got 75% of the problema correct. How many did he get correct?

Mathematics

1 answer:

vazorg [7]2 years ago

3 0

Answer:

60 problems

Step-by-step explanation:

Find how many he got correct by multiplying 80 by 0.75:

80(0.75)

= 60

So, Bill got 60 problems correct

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Anne and Nancy use a metal alloy that is 20% copper to make jewelry. How many ounces of a 14% and 24% alloy must be mixed to for

Gala2k [10]

<span>copper +copper = copper
0.14x+0.24(100-x) = 0.20*100 = 20</span>

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2 years ago

6th grade math help me, please:))

Leokris [45]

Answer:

40 percent

Step-by-step explanation:

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2 years ago

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Hi, I actually have this question not this one sorry

Ivanshal [37]

we know that

If V is the midpoint of SU

then

SV=VU

substitute the given values

2x+18=8x-6

solve for x

8x-2x=18+6

6x=24

Find SV

SV=2x+18

SV=2(4)+18

<h2>SV=26 units</h2>

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and

SU=2SV

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<h2>SU=52 units</h2>

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1 year ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

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2 years ago

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erik [133]

Answer:

Step-by-step explanation:

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