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lana [24]
3 years ago
12

A drawer has 9 pairs of white socks 7 pairs of black socks 6 pairs of brown socks and 3 pairs of blue socks you get dressed each

morning in the dark in randomly reach into the sock drawer to get your socks after a day of wearing the socks you do not replace them until the weekend after you have done some laundry what is the probability that your sock selection goes in the following order for this week?
P(Black then white then white the brown then blue)=____
Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

567/398475 in fraction or 0.0014229249 in decimal

Step-by-step explanation:

In the question, we are given these values

Total pair of socks = 25 pairs of socks

9 pairs of white socks

7 pairs of black socks

6 pairs of brown socks

3 pairs of blue socks

From the question, we can see that, this is probability without replacement.

Hence,

P(Black then white then white the brown then blue)=

7/25 × 9/24× 8/23 ×6/22 × 3/21

= 9072/6375600

= 567/398475

Therefore, the Probability of picking a Black socks then white socks then white socks , then brown socks and then blue socks = 567/398475 in fraction or 0.0014229249 in decimal

Harrizon [31]3 years ago
5 0

Answer:

0.0014 = 0.14%

Step-by-step explanation:

First we need to find the total number of pairs:

9 + 7 + 6 + 3 = 25 pairs

Then, we need to find the probability for each case:

First socks black: 7 pairs over 25: P1 = 7/25

Second socks white: 9 pairs over 24: P1 = 9/24 = 3/8

Third socks white: 8 pairs over 23: P1 = 8/23

Fourth socks brown: 6 pairs over 22: P1 = 6/22 = 3/11

Fifth socks blue: 3 pairs over 21: P1 = 3/21 = 1/7

The final probability will the the product of all probabilities above:

P = (7/25) * (3/8) * (8/23) * (3/11) * (1/7) = 0.0014 = 0.14%

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Triss [41]
130 pints per second

8 0
3 years ago
Maddie biked 8 3/4 miles today, and Chase bikes 3 1/2 miles. How many times the length of Chase’s bike ride was Maddie’s bike ri
borishaifa [10]

Answer: 2.5 times

Step-by-step explanation:

Given : The length of Chase’s bike ride= 8\dfrac{3}{4}\ miles

The length of Maddie’s bike ride=3\dfrac{1}{2}\ miles

In improper fraction : Length of Chase’s bike ride=\dfrac{4(8)+3}{4}\ miles

=\dfrac{35}{4}\ miles

Similarly , Length of Maddie’s bike ride= \dfrac{7}{2}\ miles

The number of times the length of Chase’s bike ride was Maddie’s bike ride= \dfrac{\text{ Length of Chase’s bike ride}}{\text{ Length of Maddie’s bike ride}}

=\dfrac{\dfrac{35}{4}}{\dfrac{7}{2}}\\\\=\dfrac{5}{2}=2.5

Hence, the length of Chase’s bike ride was 2.5 times Maddie’s bike ride.

8 0
3 years ago
I need this answered please
Basile [38]
I think is gonna be B


3 0
3 years ago
Read 2 more answers
James, Priya, and Siobhan work in a grocery Store. James makes $9.00 per hour. Priya makes 40% more than James, and Siobhan make
wolverine [178]

Answer:

<em>* Siobhan's profit at the grocery store ⇒ $ 10.8 *</em>

Step-by-step explanation:

See below;

Priya's 40% profit in the grocery store ⇒ 40/100 * 9 = 2/5 * 9 = 18/5 ⇒ $ 3.6,

Priya's profit at the grocery store ⇒ 9 + 3.6 ⇒ $ 12.6,

Siobhan's 15% of Priya's profit from the store ⇒ 15/100 * 12.6 = $ 1.8

Siobhan's profit at the grocery store ⇒ 12.6 - 1.8 = $ 10.8

<em>* Siobhan's profit at the grocery store ⇒ $ 10.8 *</em>

4 0
3 years ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
Read 2 more answers
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