The square pyramid with a base with edges of 6 inches and slant height of 4 inches have a surface area of 84 in².
The net of the square pyramid have a base of 6 inches and the height of each triangle is 4 inches.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
The square pyramid with a base with edges of 6 inches and slant height of 4 inches. Hence:
Surface area = (6 * 6) + 2(6 * 4) = 84 in²
The net of the square pyramid have a base of 6 inches and the height of each triangle is 4 inches.
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Answer:
it is B.
Step-by-step explanation:
B. can i have brainlyest please
The value of x is 243
(correct me if wrong)
Answer:
627square inches
Step-by-step explanation:
Area of the composite figure.. = area of triangle + area of parallelogram
Since the triangle is an equilateral triangle;
Area of the triangle = r²sintheta
Area of the triangle = 18²sin60
Area of the triangle = 324sin60
Area of the triangle = 324(0.8860)
Area of the triangle = 280.584 square in
Area of the triangle = 281 square inches
Area of parallelogram = absintheta
Area of parallelogram = 20(20)sin60
Area of parallelogram = 400(0.8660)
Area of parallelogram = 346.4square inches
Area of parallelogram = 346 square inches
Area of the figure = 346 + 281
Area of the figure = 627square inches
Formula: A = pq/2
p = d1
q = d2
Substitute with the given values and solve.
A = 12*14/2
A = 168/2
A = 84
Therefore, the ansewr is 84in²
Best of Luck!