Determine the base of right triangle by using pythagoras theorem.
![\begin{gathered} b=\sqrt[]{(15.7)^2-(8.5)^2} \\ =\sqrt[]{174.24} \\ =13.2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%3D%5Csqrt%5B%5D%7B%2815.7%29%5E2-%288.5%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B174.24%7D%20%5C%5C%20%3D13.2%20%5Cend%7Bgathered%7D)
Determine the area of base of figure.

Determine the volume of the figure.

So volume of the figure is 347.82 yards square.
15/5 goes to all of them..
15/5 = 3
Answer:
The series is convergent answer ⇒ (a)
Step-by-step explanation:
* The series is -8/5 + 32/25 + -128/125 + ........
- It is a geometric series with:
- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5
* The difference between the convergent and divergent
in the geometric series is :
- If the geometric series is given by sum = a + a r + a r² + a r³ + ...
* Where a is the first term and r is the common ratio
* If |r| < 1 then the following geometric series converges to a / (1 - r).
- Where a/1 - r is the sum to infinity
* The proof is:
∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number
∴ r^n approach to zero
∴ S = a(1 - 0)/(1 - r) = a/(1 - r)
∴ S∞ = a/1 - r
* If |r| ≥ 1 then the above geometric series diverges
∵ r = -4/5
∴ IrI = 4/5
∴ IrI < 1
∴ The series is convergent
B
calculate the slopes m of the 2 lines using the gradient formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = C(- 2, 4) and (x₂, y₂ ) = D(0, - 4 )
=
=
= - 4
repeat with (x₁, y₁ ) = F(- 4, 0 ) and (x₂, y₂ ) = G(4, 2 )
=
=
= 
The 2 lines are perpendicular because their slopes are negative reciprocals