To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer: (u^2+1) * (u-2) * (u+2)
Answer:
1. 104
2. 52
3. 52
Step-by-step explanation:
I think this is right I maybe be wrong buthere is nottees I toooks in 6th
Answer: C
Step-by-step explanation:
2×3=6, 2×2=4, so that leaves you with 2+6+4+4 which adds up to 16
Answer:
8z+12
Step-by-step explanation: