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MrRissso [65]
3 years ago
7

Find the solution of x – 13 = 25, and verify your solution using substitution.

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

x = 38

Step-by-step explanation:

x-13 = 25

Add 13 to each side

x-13+13 = 25+13

x = 38

Check

38-13 = 25

25=25

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There is an alien machine which produces seven aliens every two seconds. At this rate how many aliens will produces in one hour?
lyudmila [28]
Well, there are 60 minutes in 1 hour, and there are 60 seconds in 1 minute, so in 60 minutes, there are 60 * 60 seconds, or 3600 seconds in 60 minutes, or 1 hour, therefore, in 1 hour there are 3600 seconds.

the machine makes 7 aliens in 2 seconds, how many will it make in 3600 seconds?

\bf \begin{array}{ccll}
aliens&seconds\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
7&2\\
a&3600
\end{array}\implies \cfrac{7}{a}=\cfrac{2}{3600}\implies \cfrac{7\cdot 3600}{2}=a

that many.
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3 years ago
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How can you use the multiplication property of equality to rewrite the equation 0.6x + 4.8 = 7.2
Kobotan [32]
0.6x + 4.8 = 7.2 

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0.6x=2.4 

x=4
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3 years ago
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What’s the answer to this problem that I can not figure out
Maslowich

Answer:

-64/3 HOPE THIS HELPS if you need more help let me know

4 0
3 years ago
A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that
inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, H_0 : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, H_1 : p \neq 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

                T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } } ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

            \hat p = percentage of readers who own a particular make of car in a

                  sample of 220 = 0.30

            n = sample size = 220

So, Test statistics = \frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }

                             = -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

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zhannawk [14.2K]
I pretty sure you either add or subtract to get the answer
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