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Rufina [12.5K]
2 years ago
7

In a competative exam of 40 questions plus three months is awarded for a correct answer and minus one for every correct answer t

o find the total score for student had 11 wrong answers in his attempt of all questions.
Mathematics
1 answer:
Alex Ar [27]2 years ago
6 0

Answer:

76

Step-by-step explanation:

n a competitive exam of 40 questions, +3 is awarded for a correct answer and -1 for every wrong answer. Find the total score if a student had 11 wrong answers in his attempt of all questions.

Answers gotten wrong = 11

answers gotten right = 40 - 11 = 29

total score = (point for correct answer x number of correct answer) +  (point for wrong answer x number of wrong answer)

(+3 x 29) + (-1 x 11) = 76

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ivanzaharov [21]

Answer:  a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5

Median = (\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

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