Answer:
I know
Step-by-step explanation:
The answer should not depend on which machine or which pencil you use to
find it. If you work a problem two different ways and get two different answers,
then at least one of them is wrong, and there's a pretty good chance that both
of them are.
(9.99 of anything) + (1.11 of the same thing) = 11.1 of them
9.99 (x 10^-2) + 1.11 (x 10^-2) = <em>11.1 (x 10^-2)</em> .
Can we do any more with that ?
10^-2 = 1 / 10^2 = 1 / 100 .
11.1 x 10^-2 = 11.1 / 100 = <em>0.111</em>
Answer:
5000 students appeared in the examination.
Step-by-step explanation:
We solve this question using Venn probabilities.
I am going to say that:
Event A: Passed in Mathematics
Event B: Passed in English.
5% failed in both subjects
This means that 100 - 5 = 95% pass in at least one, which means that 
80% passed in mathematics 75% passed in english
This means that 
Proportion who passed in both:

Considering the values we have for this problem

3000 of them were passed both subjects how many students appeared in the examination?
3000 is 60% of the total t. So



5000 students appeared in the examination.