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Sliva [168]
4 years ago
8

1. What must you set a quadratic function equal to in order to solve it?

Mathematics
2 answers:
vladimir1956 [14]4 years ago
4 0

question 1: you must set the equation to 0 in order to solve the quadratic equation

Rashid [163]4 years ago
4 0

1. What must you set a quadratic function equal to in order to solve it?  

<h2> 0</h2>

ax^2 + bx + c = 0

2. Explain how to complete the square to solve a quadratic function.  

Arrange the quadratic into the standard format:

ax^2 + bx + c = 0

Write out the initial bracket:

(x + b/2)^2

Expand the initial bracket:

(x + b/2)^2 = ax^2 + b + b^2

Compare b^2 to c and adjust the equation:

c - b^2 = d

(x + b/2)^2 + d

3. What is the relationship between a directrix and focus to the graph of a quadratic function known as a parabola?

A parabola is the graph of a quadratic function. (See Attachment). It is also the set of all points whose distance is from the focus is equal to the distance from the directrix.

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The width of a rectangle is 14 cm less than
ratelena [41]

Answer:

the length should be 28.5 cm.

Step-by-step explanation:

i used the equation  2L+2W=P (or L+L+W+W=P)

(length + length +width + width = perimeter)

I plugged the given information into this equation so i had:

2L+(2L-14)=86

then i solved for L

(this is what that work would look like if you need it):

2L + 2(L - 14) = 86

1. distribute the 2 in 2(L-14):

2L + 2L - 28 = 86

2. combine like terms:

4L - 28 = 86

3. add 28 to both sides:

4L = 114

4. divide both sides by 4

L = 28.5

hope this helped :)

6 0
3 years ago
What is the actual distance between sauger ties and Kingston?
mrs_skeptik [129]
 the answer is 17.68 kilometers <span>10.98 miles</span>
6 0
3 years ago
Help, please HELPPPP<br>HELPPP<br>HELPP<br><br>I will follow and mark u as a brilliant
Dahasolnce [82]
41. A. 30
42. 148 because supplementary angles equal 180
3 0
3 years ago
¿En cuál de los siguientes intervalos están solo los números reales que pertenecen a ] –3 , 5 ] y no pertenecen a [ –1 , 7 [?
vitfil [10]

Complete question:

¿En cuál de los siguientes intervalos están solo los números reales que pertenecen a  ]- 3,5 ]   y no pertenecen a  [ –1 , 7 [  ?

A)  ]-3, -1[  

B)   ]- 3, -1 ]

C)  [-1,5]

D)  ]- 3,7[

E)  [5,7[

Answer:

A)  ]-3, -1[

Step-by-step explanation:

El intervalo ]- 3,5 ] incluye a todos los números que se encuentran entre -3 y 5. Es decir,

...-6  -5  -4  -3  -2  -1  0  1  2  3  4  5  6...

El intervalo  [–1 , 7[ excluye a los números que se encuentran entre -1 y 7, pero incluye a todos los números que sean menores a -1 y a todos los mayores a 7. Es decir,

...-7  -6  -5  -4  -3  -2  -1  0  1  2  3  4  5  6  7  8  9  10  11  12  13...

Para responder el problema, debemos encontrar aquellos números reales que se<u> </u><u>incluyan</u> dentro de <u>ambos intervalos</u>. Esto es,

            ]- 3,5 ] ...-6  -5  -4 <u> </u><u>-3  -2  -1</u>  0  1  2  3  4  5  6  7  8  9  10...

]- ∞ , -1[ ∪ [7,∞[...-6  -5  -4  <u>-3  -2  -1</u>  0  1  2  3  4  5  6  7 8  9  10...

Es decir que el intervalo  ]-3, -1[, corresponde a la intersección entre ambos conjuntos.

8 0
3 years ago
Help me answer this thanks
nlexa [21]

Answer: -----68mm-------

Step-by-step explanation:

3 0
4 years ago
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