Answer:
65.38degrees
Step-by-step explanation:
Given the following
Length of ladder = 12foot = hypotenuse
Distance of the ladder from the wall = 5ft = adjacent
Required
Angle between the ground and the ladder theta
Using the SOH CAH TOA identity
Cos theta = adj/hyp
Cos theta = 5/12
Cos theta = 0.41667
theta = arccos(0.41667)
theta = 65.38 degrees
Hence the angle between the ground and the floor is 65.38degrees
Wow that's a hard one. Ummm....
Answer:
No is correct
Step-by-step explanation:
convert 2/3 into 6ths
4/6 = 8/12
so no, non of them equal to 4/8
> multiply the second equation by 2 and add it to the first equation.
2(-6x - 7y = -10)
-12x -14y = -20
8x + 14y = 4
-12x - 14y = -20
--------------------
- 4x + 0 = - 16
x = -16/-4
x = 4
> use x = 4 in either equation to find y
8(4) + 14y = 4
32 + 14y = 4
14y = 4 - 32
14y = -28
y = -28/14
y = -2
