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2 years ago

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The seats at a local baseball stadium are arranged so that each row has five more seats than the row below it. If there are 4 se

ats in the 1st row, how many seats are in row 23?

1 answer:

nordsb [41]2 years ago

4 0

Givens:

a = 4; n = 23; d = 5

Formula

L = a + (n - 1)*d

Substitute and solve

L = 4 + (23 - 1)*5

L = 4 + 22*5

L = 4 + 110

L = 114 Answer

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Answer both please man. Or sorry you'll get a 1 star rating. THanks for answering guys!

Nataliya [291]

For the first one,

x = 10.

For the second one,

x = 12

5 0

3 years ago

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Ashton made contributions to a Roth IRA over the course of 32 working years. His contributions averaged $2,400 annually. Ashton

enyata [817]

The formula of the future value of an annuity ordinary is
Fv=pmt [(1+r)^(n)-1)÷r]
Fv future value?
PMT 2400
R 0.08
T 32 years
Fv=2,400×((1+0.08)^(32)−1)÷(0.08)
Fv=322,112.49
Now deducte 28% the tax bracket from the amount we found
annual tax 2,400×0.28 =672 and tax over 32 years is 672×32 =21,504. So the effective value of Ashton's Roth IRA at retirement is 322,112.49−21,504=300,608.49

3 0

3 years ago

The diagram below shows a square inside a regular octagon. The apothem of the octagon is 15.69 units. To the nearest square unit

Musya8 [376]

Answer:

C. 647 square units

Step-by-step explanation:

To find the shaded area, subtract the area of the unshaded square from the area of the octagon.

<u>Area of the octagon</u>

$\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}$

where:

n = number of sides
l = length of one side
a = apothem

Given:

n = 8
l = 13
a = 15.69

Substitute the given values into the formula and solve for A:

$\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}$

$\implies \textsf{Area}=\sf \dfrac{1631.76}{2}$

$\implies \textsf{Area}=\sf 815.88\:\:square \:units$

<u>Area of the square</u>

$\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units$

<u>Area of the shaded region</u>

= area of the octagon - area of the square

= 815.88 - 169

= 646.88

= 647 square units (nearest square unit)

3 0

2 years ago

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Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)

timama [110]

<h3>Answer: c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

$f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\$

With a = -5 and b = 4, we have

$f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\$

So,

$f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\$

Use algebra to solve for c

$-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\$

6 0

2 years ago

Which function does the graph represent

myrzilka [38]

Answer:

The answer is d

Step-by-step explanation:

I graphed it

-b/2a to get the vertex

3x^2-12+9

-(-12)/(2)(3)=2

plug in 2 to the function

12-24+9=-3 which is the y value on the graph

(2,-3) is the vertex

3 0

3 years ago

Read 2 more answers