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vaieri [72.5K]
3 years ago
15

During the formation of the aurora borealis, the electrons in an atom experience a change in energy levels. Which statement abou

t this change is accurate?
First, the electron releases energy to move to a higher energy level.

First, the electron absorbs energy to move to a higher energy level.

First, the electron absorbs energy to move to a lower energy level.

First, the electron releases energy to move to a lower energy level.
Physics
2 answers:
adelina 88 [10]3 years ago
6 0

First, the electron absorbs energy to move to a higher energy level.

Elena L [17]3 years ago
4 0

Answer:

They are deflected as Earth’s magnetic field exerts force on them.

Explanation:

(Not for cheating, Just to help)

As solar wind approaches Earth, what happens to the charged electrons?

They are absorbed as Earth’s magnetic field exerts force on them.

They grow stronger as Earth’s magnetic field exerts force on them.

They grow weaker as Earth’s magnetic field exerts force on them.

They are deflected as Earth’s magnetic field exerts force on them.

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sesenic [268]

Answer:

the value of force, F=4.0N

Explanation:

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7 0
2 years ago
At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet
expeople1 [14]

As we know that KE and PE is same at a given position

so we will have as a function of position given as

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

also the PE is given as function of position as

PE = \frac{1}{2}m\omega^2x^2

now it is given that

KE = PE

now we will have

\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2

A^2 - x^2 = x^2

2x^2 = A^2

x = \frac{A}{\sqrt2}

so the position is 0.707 times of amplitude when KE and PE will be same

Part b)

KE of SHO at x = A/3

we can use the formula

KE = \frac{1}{2}m\omega^2(A^2 - x^2)

now to find the fraction of kinetic energy

f = \frac{KE}{TE} = \frac{A^2 - x^2}{A^2}

f = \frac{A^2 - (\frac{A}{3})^2}{A^2}

f_k = \frac{8}{9}

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

f_{PE} = 1 - f_k

f_{PE} = 1 - (8/9) = 1/9

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