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vaieri [72.5K]
3 years ago
15

During the formation of the aurora borealis, the electrons in an atom experience a change in energy levels. Which statement abou

t this change is accurate?
First, the electron releases energy to move to a higher energy level.

First, the electron absorbs energy to move to a higher energy level.

First, the electron absorbs energy to move to a lower energy level.

First, the electron releases energy to move to a lower energy level.
Physics
2 answers:
adelina 88 [10]3 years ago
6 0

First, the electron absorbs energy to move to a higher energy level.

Elena L [17]3 years ago
4 0

Answer:

They are deflected as Earth’s magnetic field exerts force on them.

Explanation:

(Not for cheating, Just to help)

As solar wind approaches Earth, what happens to the charged electrons?

They are absorbed as Earth’s magnetic field exerts force on them.

They grow stronger as Earth’s magnetic field exerts force on them.

They grow weaker as Earth’s magnetic field exerts force on them.

They are deflected as Earth’s magnetic field exerts force on them.

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True . this is called a complex substance
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Carbon is allowed to diffuse through a steel plate 15 mm thick. The concentrations of carbon at the two faces are 0.65 and 0.30
beks73 [17]

Answer:

T=575.16K

Explanation:

To solve the problem we proceed to use the 1 law of diffusion of flow,

Here,

J=-D\frac{\Delta C}{\Delta x}

\Delta C is the rate in concentration

\Delta xis the rate in thickness

D is the diffusion coefficient, where,

D= D_0 exp(\frac{Q_d}{RT})

Replacing D in the first law,

J=-(D_0 exp(\frac{-Q_D}{RT}))\frac{\Delta }{\Delta x}

clearing T,

T=\frac{Q_d}{R*ln(\frac{J*\Delta x}{D_0*\Delta C})}

Replacing our values

T=-\frac{80000}{8.31*ln(\frac{(6.2*10^{-7})(-15*10^{-3})}{(1.43*10^{-9})(0.65-0.30)})}

T=-\frac{80000}{-138.09}

T=575.16K

4 0
4 years ago
Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an
Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

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1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

8 0
4 years ago
Find the minimum radius of a helium balloon that will lift her off the ground. the density of helium gas is 0.178 kg/m3, and the
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Volume of balloon = \frac{4}{3} \pi r^{3}

Where r is the radius of balloon.

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Mass of air displaced by a balloon with volume V = 1.29*V

Mass of helium inside balloon = 0.178*V

Total mass to be lifted by balloon = 68 +0.178*V

Buoyant force = 1.29V-0.178V=1.112V

So we have 1.112 V =  68+ 0.178*V

   0.934 V = 68

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    \frac{4}{3} \pi r^{3}[/tex]= 72.81

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So radius of helium balloon = 2.59 m

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What describes the particles in a liquid
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Answer:

liquid a particles slides past pother

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