Answer:
Part a)

Part b)

Part c)


Explanation:
Part a)
As we know that frequency = 1 MHz
speed of electromagnetic wave is same as speed of light
So the wavelength is given as



Part b)
As we know the relation between electric field and magnetic field



Part c)
Intensity of wave is given as



Pressure is defined as ratio of intensity and speed


Explanation:
(a) Since, it is given that the blocks are identical so distribution of charge will be uniform on both the blocks.
Hence, final charge on block A will be calculated as follows.
Charge on block A =
= 4.35 nC
Therefore, final charge on the block A is 4.35 nC.
(b) As it is given that the positive charge is coming on block A
. This means that movement of electrons will be from A to B.
Thus, we can conclude that while the blocks were in contact with each other then electrons will flow from A to B.
Unless if all forces cancel each other out , the object will no longer be in equilibrium
<h2>
<u>Required</u><u> </u><u>Answer</u><u>:</u></h2>
The body will <u>stay at rest </u>(Option D). It is because a force of magnitude 50 N is pulled towards left and another force is pulling it towards right with same magnitude 50 N. So, the direction of force is opposite and magnitude is same i.e. 50 N. So, they will cancel each other and net force is 0. Hence, there would be no acceleration.
- Option A - Showing acceleration
- Option B - Showing acceleration
- Option C - Change of direction due to Net force
Hence, these options are incorrect because they are only possible when net external force is non-zero. Staying at rest i.e. Option D means there is no motion and hence no acceleration, this shows that net force is 0
<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer:
V = 48 Volts
Explanation:
Since we know that electric potential is a scalar quantity
So here total potential of a point is sum of potential due to each charge
It is given as

here we have potential due to 50 nC placed at y = 6 m



Now potential due to -80 nC charge placed at x = -4



Now potential due to 70 nC placed at y = -6 m



Now total potential at this point is given as
