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2 years ago

The photograph shows a kettle made of the element copper. Which statement describes a chemical property of copper?

Physics

2 answers:

Aleks04 [339]2 years ago

7 0

A copper forms a patina when it interacts with air

bixtya [17]2 years ago

5 0

Answer A
Explanation
B describes its matter (composition)
C describes its ability to conduct
D describes is mailability

A describes a chemical reaction with the air

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A 1-meter-long wire consists of an inner copper core with a radius of 1.0 mm and an outer aluminum sheathe, which is 1.0 mm thic

Mazyrski [523]

Answer:

The total resistance of the wire is = $1.917\times10^{-3}$

Explanation:

Since the wires will both be in contact with the voltage source at the same time and the current flows along in their length-wise direction, the two wires will be considered to be in parallel.

Hence, for resistances in parallel, the total resistance, $R_{Total}$

$\frac{1}{R_{Total}} =\frac{1}{R_{cu} }+\frac{1}{R_{al}}$

Parameters given:

Length of wire = 1 m

Cross sectional area of copper $A_{cu}= \pi r^{2}= \pi \times (1\times 10^{-3} )^{2} =3.142\times10^{-6} m^{2}$

Cross sectional area of aluminium wire

$A_{al}= \pi( R^{2}-r^{2})\\\\ = \pi \times [ (2\times 10^{-3} )^{2}-(1\times 10^{-3} )^{2}] =9.42\times10^{-6} m^{2}\\$

Resistivity of copper $\rho _{cu}=1.7\times 10^{-8} \Omega .m$

Resistivity of Aluminium $\rho _{al}=2.8\times 10^{-8} \Omega .m$

Resistance of copper $R_{cu}= \frac{\rho_{cu} \times l}{A_{cu} } =\frac{1.7\times 10^{-8} \times 1}{3.142\times10^{-6} } =5.41\times 10^{-3}\Omega$

Resistance of aluminium $R_{al}= \frac{\rho_{al} \times l}{A_{al} } =\frac{2.8\times 10^{-8} \times 1}{9.42\times10^{-6} } =2.97\times 10^{-3}\Omega$

The total resistance of the wire can be obtained as follows;

$\frac{1}{R_{Total}} =\frac{1}{5.41\times10^{-3} }+\frac{1}{2.97\times10^{-3}}=521.52\frac{1}{\Omega}$

$R_{Total}= 1.917\times 10^{-3}\Omega$

∴ The total resistance of the wire = $1.917\times 10^{-3}\Omega$

4 0

3 years ago

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You are making a telephone out of two aluminum cans and some string. You can choose between two types of string: a 2-m length of

Nataliya [291]

Answer:

C)You should use the thin cooking twine.

Explanation:

A)You can choose either because they are the same length and will produce the same wave speed.

B)You should use the heavy rope.

C)You should use the thin cooking twine.

The speed of wave in a string is given by the following formula:

| $v$ | = $\sqrt{\frac{F_T}{u} }$

Where | $v$ | = speed of wave, $F_T$ = tension in the string, and μ = mass per length of the string.

Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the $F_T$ :μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger | $v$ |.

Therefore, the thin rope should be used in order to get a faster wave speed in the telephone.

The correct option is C.

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3 years ago

Which other subatomic particle has the same mass as a neutron

RideAnS [48]

Answer:

.................... protons :)

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3 years ago

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What is the weight of a 5.00 kg object on Earth? Assume g=9.81 m/s^2.