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2 years ago

A 1000kg ar accelerates from rest to 25.0m/s in 4.20

Physics

1 answer:

bezimeni [28]2 years ago

7 0

Answer:

74.4 kilowatts or 99.8 horsepower

Explanation:

The explanation is in the attachment.

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Two friends are walking on a hot beach on a hot summer day. one friend reports her feet are becoming hot she needs her sandals.

nata0808 [166]

Answer:

conduction

Explanation:

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2 years ago

Ai là người phát hiện trái đất hình cầu đầu tiên ?

Scorpion4ik [409]

Answer:

Can't understand the language

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2 years ago

When two forces are acting a body in opposite direction their resultant become 6N and when they are acting in the same direction

Norma-Jean [14]

Answer:

9 and 3 N

Explanation:

Forces in the same direction sum up to produce the resultant force;

One force subtract the other will give the resultant force when they are in opposite directions;

Lets say one direction is forwards and the opposite backwards;

We have one force, let's say force A, in the forwards direction and another force, force B, acting in the same (forwards) or opposite (backwards) direction;

If B is acting in the same direction, then the resultant force (in this case) will be as follows:

A + B = 12

If B is acting in the opposite direction, then the resultant force will be as follows:
A - B = 6

Summing the two equations will allow us to solve for A:

A + B + (A - B) = 12 + 6

2A = 18

A = 9

Substitute this into either of the above equations and we can solve for B:
(9) - B = 6

B = 9 - 6

B = 3

5 0

2 years ago

A device used to measure a mass of an object is called

OLga [1]

Answer:

I am explain you in image

8 0

3 years ago

A 26.5-g object moving to the right at 20.5 cm/s overtakes and collides elastically with a 12.5-g object moving in the same dire

Dahasolnce [82]

Answer:

v₁ =0.19 m/s and v₂ = 0.18 m/s

Explanation:

By conservation of energy and conservation of momentum we can find the velocity of each object after the collision:

Momentum:

Before (b) = After (a)

$m_{1}v_{1b} + m_{2}v_{2b} = m_{1}v_{1a} + m_{2}v_{2a}$

$26.5 kg*0.205 m/s + 12.5 kg*0.150 m/s = 26.5 kg*v_{1a} + 12.5 kg*v_{2a}$ $7.31 kg*m/s = 26.5 kg*v_{1a} + 12.5 kg*v_{2a}$ (1)

Energy:

Before (b) = After (a)

$\frac{1}{2}m_{1}v_{1b}^{2} + \frac{1}{2}m_{2}v_{2b}^{2} = \frac{1}{2}m_{1}v_{1a}^{2} + \frac{1}{2}m_{2}v_{2a}^{2}$

$26.5 kg*(0.205 m/s)^{2} + 12.5 kg*(0.150 m/s)^{2} = 26.5 kg*v_{1a}^{2} + 12.5 kg*v_{2a}^{2}$

$1.40 J = 26.5 kg*v_{1a}^{2} + 12.5 kg*v_{2a}^{2}$ (2)

From equation (1) we have:

$v_{2a} = \frac{7.31 kg*m/s - 26.5 kg*v_{1a}}{12.5 kg}$ (3)

Now, by entering equation (3) into (2) we have:

$1.40 J = 26.5 kg*v_{1a}^{2} + 12.5 kg*(\frac{7.31 kg*m/s - 26.5 kg*v_{1a}}{12.5 kg})^{2}$ (4)

By solving equation (4) for $v_{1a}$ , we will have two values for

$v_{1a} = 0.16$

$v_{1a} = 0.21$

We will take the average of both values:

$v_{1a} = 0.19 m/s$

Now, by introducing this value into equation (3) we can find $v_{2a}$ :

$v_{2a} = \frac{7.31 kg*m/s - 26.5 kg*0.19 m/s}{12.5 kg}$

$v_{2a} = 0.18 m/s$

Therefore, the velocity of object 1 and object 2 after the collision is 0.19 m/s and 0.18 m/s, respectively.

I hope it helps you!

6 0

2 years ago