Find the area of each sector

Mathematics

1 answer:

lions [1.4K]3 years ago

3 0

Answer:

$Area = \frac{\theta}{360} \times \pi r^2\\\\$

$= \frac{150}{360}\pi \times 16 \times16= \frac{320\pi }{3} mi^2$

option D

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When 0.3(4x - 8) - 0.5(2.4x + 4) is simplified what is the resulting expression?

LUCKY_DIMON [66]

0.3(4x-8)-0.5(2.4x+4)
1.2x-2.4-1.2x+2
x-0.4

4 0

3 years ago

Gekata [30.6K]

Answer:

A. A(n) = 150 • (0.74)^n–1 ; 33.29 cm

Step-by-step explanation:

This is a geometric sequence.

a%5B1%5D=1.5m=150cm, r=0.74

The formula is

a%5Bn%5D=a%5B1%5Dr%5E%28n-1%29

Just substitute a1 = 150cm and r = 0.74

a%5Bn%5D=150%280.74%29%5E%28n-1%29

That's the rule.

For the second part, substitute n = 6

cm.

7 0

2 years ago

Solve the system by substitution.<br> - 8x + y = -32<br> - 3x – 10 = y<br> (,)

agasfer [191]

Answer:

$x=2,\:y=-16$

Step-by-step explanation:

$\begin{bmatrix}-8x+y=-32\\ -3x-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:-8x+y=-32:\quad x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}x=-\frac{-32-y}{8}\\\begin{bmatrix}-3\left(-\frac{-32-y}{8}\right)-10=y\end{bmatrix}\\\\Simplify\\\begin{bmatrix}\frac{3\left(-32-y\right)}{8}-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:\frac{3\left(-32-y\right)}{8}-10=y:\quad y=-16\\\\\mathrm{For\:}x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}y=-16\\x=-\frac{-32-\left(-16\right)}{8}\\$