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2 years ago

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A bag contains 8 red balls and 6 blue

1 answer:

Andreyy892 years ago

5 0

Answer:

The probability that all 3 balls are red is 18.65%, while the probability that all 3 balls are blue is 7.87%.

Step-by-step explanation:

Since a bag contains 8 red balls and 6 blue balls, and Radhika takes three balls at random from the bag, without replacement, to calculate the probability that the three balls are the same color, the following mathematical operations must be performed:

8 + 6 = 14

14 = 100

8 = X

8 x 100/14 = X

800/14 = X

57.14 = X

100 - 57.14 = 42.86

0.5714 ^ 3 = X

0.1865 = X

0.4286 ^ 3 = X

0.0787 = X

Therefore, the probability that all 3 balls are red is 18.65%, while the probability that all 3 balls are blue is 7.87%.

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(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

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Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

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3 years ago