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3 years ago

HELP ASAP!!!!!!! PLEASE WILL GIVE BRAINLIEST

Physics

2 answers:

blagie [28]3 years ago

8 0

Answer:

They carry out essential functions that are necessary for the survival of cells – harvesting energy, making new proteins, getting rid of waste. Hope this helps!

Explanation:

MAXImum [283]3 years ago

3 0

I organelles is a specialized subunits with a specific cell, their general function is to store genetic information

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I need help with these question ASAP .. I have to get them done tonight because it is due tomorrow

Yuki888 [10]

Answer:

It's letter B that's all I know

8 0

2 years ago

A beam of light has a wavelength of 620 nm in vacuum.

crimeas [40]

Explanation:

It is given that,

Wavelength of a beam of light in vacuum, $\lambda_o=620\ nm$

(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.

We know that,

Refractive index,

$n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s$

(b) The wavelength of light in material,

$\lambda=\dfrac{\lambda_o}{n}$

Let $\lambda_1$ is the wavelength of these waves in the liquid. So,

$\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m$

Hence, this is the required solution.

7 0

4 years ago

A research vessel is mapping the bottom of the ocean using sonar. It emits a short sound pulse called "ping" downward. The frequ

Svetradugi [14.3K]

Answer:

d = 4180.3m

wavelengt of sound is 0.251m

Explanation:

Given that

frequency of the sound is 5920 Hz

v=1485m/s

t=5.63s

let d represent distance from the vessel to the ocean bottom.

an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.

$velocity=\frac{distance}{time}\\\\ v=\frac{2d}{t} \\\\vt=2d\\\\d=\frac{vt}{2}$

$d=\frac{1485*5.63}{2}\\d= 4180.3m$

wavelengt of sound is $\lambda$ = v/f

= (1485)/(5920)

= 0.251 m

7 0

3 years ago

1. बालू के एक कण की त्रिज्या 1.6 x 10-4मी है। इस कण की त्रिज्या

Over [174]

Answer:

BOIIII english????

Explanation:

5 0

4 years ago

Calculate the force of an 8kg object pushing up from the table

zepelin [54]

The correct answer to the question is: 78.4 N.

CALCULATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the force of 8 Kg object pushing up from the table.

The force pushing up from the table is nothing else than the normal reaction.

The normal reaction of the object is equal to the weight of the object as the object is simply resting on the table.

Hence, normal reaction = Weight

= mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the force of the object pushing up from the table is 78.4 N.

6 0

4 years ago