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Andreas93 [3]
3 years ago
12

In a Joule experiment, a mass of 6.51 kg falls through a height of 66.8 m and rotates a paddle wheel that stirs 0.68 kg of water

. The water is initially at 15 degrees C. By how much does its temperature rise (in degrees C)
Physics
1 answer:
MatroZZZ [7]3 years ago
5 0

Explanation:

As the given data is as follows.

         m = 6.51 kg,   g = 9.8 m/s^{2},     h = 66.8 m

mass of water (M) = 0.68 kg,    Specific heat of water = 4200 J/kg^{o}C

    T_{1} = 15^{o}C

According to the given situation, the decrease in potential energy of mass will be equal to heat energy gained by water.

Therefore,

                mgh = m \times C \times (T_{f} - T_{i})

    6.51 kg \times 9.8 \times 66.8 m = 0.68 kg \times 4200 J/kg^{o}C \times (T_{f} - 15)^{o}C

        4261.7064 = 2856 (T_{f} - 15)^{o}C

              1.492 = T_{f} - 15

              T_{f} = 16.492^{o}C

So,    \Delta T = (16.492 - 15)^{o}C

                       = 1.492^{o}C

Therefore, we can conclude that rise in temperature will be 1.492^{o}C.

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