A small charged bead has a mass of 1.0 g. It is held in a uniform electric field of magnitude E = 200,000 N/C, directed upward.
1 answer:
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Answer:
Force=29789.55 N
Explanation:
Given data
dimension=3.5m by 2.1m
P(outside pressure)=0.96 atm
P(inside pressure)=1.00 atm
Force=?
Solution
Area=L×W
A=(3.5)×(2.1)
As we know
F=PA
For P(pressure)
P=P(inside)-P(outside)
P=1.00-0.96
P=0.04 atm
convert atm to pascal (pa) we get
P=4053 pa
F=PA
F=(4053)×(7.35)
F=29789.55 N
Answer:
17.10 m
Explanation:
When the toboggan stops, we have:
The x-component of weight is the product of the weight and the sine of the angle above the horizontal, so the y-component of W is the product of the weight and the cosine of the angle above the horizontal.
The work-energy principle states that the change in the kinetic energy of an object is equal to the net work done on the object.
Recall that , replacing (1):
<u>Answer:</u>
Displacement after 1 second = 4.9 m
Displacement after 2 seconds = 19.6 m
Displacement after 3 seconds = 44.1 m
Velocity after 1 second = 9.8 m/s
Velocity after 2 seconds = 19.6 m/s
Velocity after 3 seconds = 29.4 m/s
<u>Explanation:</u>
We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Height of building, displacement = 381 meter
Initial velocity = 0 m/s
Acceleration = Acceleration due to gravity = 9.8
Displacement after 1 second =
Displacement after 2 seconds =
Displacement after 3 seconds =
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
Velocity after 1 second = 0 + 9.8 * 1 = 9.8 m/s
Velocity after 2 seconds = 0 + 9.8 * 2 = 19.6 m/s
Velocity after 3 seconds = 0 + 9.8 * 3 = 29.4 m/s