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harina [27]
4 years ago
5

A bird sitting high in a tree is an example of an object with what type of energy?

Physics
2 answers:
Nostrana [21]4 years ago
8 0
It has potential energy because of its position.
Oksanka [162]4 years ago
5 0
It's potential energy because it is not in motion .
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Place thermometers near the edge of the table for easy retrieval.
Maurinko [17]
This is a true and false question correct or did you accidentally put two truths ??
7 0
4 years ago
One of the principal difficulties in establishing the theory of continental drift (the idea that tectonic plates drift around on
iragen [17]

Answer:

The energy that drives this movement is heat within the earth, this heat comes from two main sources which are;

1) residual heat left over from the formation of our planet billions of years ago.

2) The radioactive decay of naturally occurring chemical elements (notably uranium, thorium, and potassium ) in the earth releases energy in the form of heat. These two sources of heat warm Earth’s mantle and cause it to rise and sink, this rising and sinking creates a convectional movement of earth mantle.

4 0
4 years ago
If a car is driving at 10 m/s and is driving for 2 minutes, what is the total distance it will
kondor19780726 [428]

Distance = (speed) x (time)

Distance = (10 meter/second) x (2 minutes)

Distance = (10 meter/second) x (2 minutes) x (60 second/minute)

Distance = (10 x 2 x 60) (meter-minute-second / second-minute)

<em>Distance = 1,200 meters</em>

4 0
3 years ago
A drowsy cat spots a flower pot that sails first up and then down past an open window. The pot was in view for a total of 0.56 s
liberstina [14]

Answer:

h = 0.028 m

Explanation:

As we know that

d = \frac{v_2 + v_1}{2} t

here we have

1.95 = \frac{v_2 + v_1}{2}(0.56)

v_2 + v_1 = 6.96

also we know

v_2 - v_1 = at

v_2 - v_1 = (9.81)(0.56)

v_2 - v_1 = 5.49

so we have

v_2 = 6.23 m/s

v_1 = 0.74 m/s

so the height above window is given as

v_f^2 - v_i^2 = 2 a d

0.74^2 - 0 = 2(9.81)h

h = 0.028 m

4 0
4 years ago
A proton moves through a region of space where there is a magnetic field B⃗ =(0.64i+0.40j)T and an electric field E⃗ =(3.3i−4.5j
fenix001 [56]

Answer:

F = (8.35 \times 10^{-16})\hat i - (12.12 \times 10^{-16})\hat j +(1.35 \times 10^{-16})\hat k

Explanation:

When a charge is moving in constant magnetic field and electric field both then the net force on moving charge is vector sum of force due to magnetic field and electric field both

so first the force on the moving charge due to electric field is given by

\vec F_e = q\vec E

\vec F_e = (1.6 \times 10^{-19})(3.3 \hat i - 4.5 \hat j) \times 10^3

\vec F_e = (5.28 \times 10^{-16}) \hat i - (7.2 \times 10^{-16}) \hat j

Now force on moving charge due to magnetic field is given as

\vec F_b = q(\vec v \times \vec B)

\vec F_b = (1.6 \times 10^{-19})((6.6 \hat i+2.8 \hat j−4.8 \hat k) \times 10^3 \times (0.64 \hat i + 0.40 \hat j) )

\vec F_b = (4.22 \times 10^{-16})\hat k - (2.87 \times 10^{-16})\hat k - (4.92 \times 10^{-16})\hat j + (3.07 \times 10^{-16}) \hat i

\vec F_b = (3.07\times 10^{-16})\hat i - (4.92 \times 10^{-16})\hat j + (1.35 \times 10^{-16})\hat k

Now net force due to both

F = F_e + F_b

F = (8.35 \times 10^{-16})\hat i - (12.12 \times 10^{-16})\hat j +(1.35 \times 10^{-16})\hat k

7 0
3 years ago
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