We have that The force exerted by the cable at point B on the pole is
From the Diagram
We can see that A,B.C is the area showing the circumference of a cable(power line)
Generally the equation for the Tension is mathematically given as
In conclusion
The force exerted by the cable at point B on the pole is
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When you double capacitance and inductance, the new resonance frequency becomes halved.
What is Resonance frequency?
It is the natural frequency of an object where it tends to vibrate at a higher amplitude.
The resonance frequency of the LC series circuit is the frequency at which the capacity reactance is equal to inductive reactance.
The formula resonance frequency:
where;
f0 is the resonance frequency
L is the inductance
C is the capacitance
here, if the capacitance and inductance are doubled, the new resonance frequency becomes;
Thus from the above equation for frequency,
When you double capacitance and inductance, the new resonance frequency becomes f(0) / 2.
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Answer:
direction, speed, and shape of a body
Explanation:
Answer: check explanation.
Explanation:
The acceleration of the system means the acceleration of the centre of mass of the system. So, let's take a quick look at the first two laws of Newton.
Newton's first law states that any object at rest that is not acted upon by outside forces will remain at rest, and that any object in motion not acted upon by outside forces will continue its motion in a straight line at a constant velocity. This laws seems to be at odd with our everyday lives. Let's take a look at the his second law.
Mathematically, the second law can be represented as; F=Ma. The law states that object will accelerate in the direction of the net force.
In order to know the acceleration of attached objects attached to a pulley we need to consider the system of objects as one object, followed by measuring the effect of the net external forces with respect to the ratio of the total mass of the system.
Answer:
114.44 J
Explanation:
From Hook's Law,
F = ke................. Equation 1
Where F = Force required to stretch the spring, k = spring constant, e = extension.
make k the subject of the equation
k = F/e.............. Equation 2
Given: F = 10 lb = (10×4.45) N = 44.5 N, e = 4 in = (4×0.254) = 1.016 m.
Substitute into equation 2
k = 44.5/1.016
k = 43.799 N/m
Work done in stretching the 9 in beyond its natural length
W = 1/2ke²................. Equation 3
Given: e = 9 in = (9×0.254) = 2.286 m, k = 43.799 N/m
Substitute into equation 3
W = 1/2×43.799×2.286²
W = 114.44 J