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2 years ago

Weird question but, whenever you divide by 1/4 or multiply by 4/1, will you always get the same answer.

Mathematics

1 answer:

professor190 [17]2 years ago

8 0

Answer:

yep

Step-by-step explanation:

when you divide a fraction u can use the KCF method which is basically:

(keep) the first fraction the same

(change) the division sign in the middle to a multiplication sign

(flip) the second fraction

basically because you have to flip the 1/4 when you divide it, it'll be the same as a 4/1 anyways

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43 milk jugs are in a fridge with 11 that are spoiled. 5 jugs are randomly selected. what are the odds that the first two are go

malfutka [58]

Answer:

0.85% probability that the first two are good and the last three are spoiled

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the first two jugs is not important, as is not the order in which the last three are selected. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

2 spoiled, from a set of 43-11 = 32.

3 spoiled, from a set of 11.

$D = C_{32,2}*C_{11,3} = \frac{32!}{2!(32-2)!}*\frac{11!}{3!(11-3)!} = 982080$

Total outcomes:

5 jugs from a set of 43.

$T = C_{43,5} = \frac{43!}{5!(43-5)!} = 115511760$

Probability:

$p = \frac{D}{T} = \frac{982080}{115511760} = 0.0085$

0.85% probability that the first two are good and the last three are spoiled

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3 years ago

Please help me with this question

inna [77]

What data is the table referring to?

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3 years ago

Which of the following equations have complex roots?

mestny [16]

Answer:

Step-by-step explanation:

Complex roots of quadratic functions occur when the discriminant is negative.

Discriminant

$b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0$

Evaluate the discriminant of each of the given equations.

$\textsf{A.} \quad 3x^2+2=0$

$\implies a=3, \quad b=0, \quad c=2$

$\implies b^2-4ac=0^2-4(3)(2)=-24$

As -24 < 0 the equation will have complex roots.

$\textsf{B.} \quad 2x^2+1=7x$

$\implies 2x^2-7x+1=0$

$\implies a=2, \quad b=-7, \quad c=1$

$\implies b^2-4ac= (-7)^2-4(2)(1)=41$

As 41 > 0 the equation does not have complex roots.

$\textsf{C.} \quad 3x^2-1=6x$

$\implies 3x^2-6x-1=0$

$\implies a=3, \quad b=-6, \quad c=-1$

$\implies b^2-4ac=(-6)^2-4(3)(-1)=48$

As 48 > 0 the equation does not have complex roots.

$\textsf{D.} \quad 2x^2-1=5x$

$\implies 2x^2-5x-1=0$

$\implies a=2, \quad b=-5, \quad c=-1$

$\implies b^2-4ac=(-5)^2-4(2)(-1)=33$

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

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Learn more about complex roots here:

brainly.com/question/26344541

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