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77julia77 [94]
3 years ago
5

1 + 2k = 5k + 7 I got k=2 don't know if it's the right answer ?

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
You are close, but it is not the correct answer.

1 + 2k = 5k + 7

First, since we are trying to get the variable by itself, we need to move all things to one side. Let's subtract 1 from each side. 
2k = 5k + 7 - 1

Second, we can now subtract (7 - 1) to get 6. Let's add that into our problem and then subtract 5 from each side, still trying to get the variable by itself.
2k - 5k = 6

Third, subtract (2k - 5k) to get -3k. Hint the negative symbol now. If the problem were switched the other way, it would still be a positive. 
-3k = 6

Fourth, we can now divide each side by -3. This results in a fraction and also getting the variable by itself on one side of the problem. Remember the negative sign in front of the fraction since (-3) carried it.
k = - \frac{6}{3}

Fifth, this is our last step. We need to simplify the fraction. Since out fraction is 6/3, which number multiples by 3 to get the answer of 6? The answer is 2, since (3 × 2 = 6). Don't forget the negative!
k = -2

Answer: \fbox {k = -2}
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Step-by-step explanation:

Here, the needed table is attached for the reference.

Now, as we can see from the table:

The distance covered by  Cindy  = 2 yards, 1 foot 3 inches

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The distance covered by  Monique   = 7 feet, 4 inches

As we know : 1 yard  =  3 feet

So, the distance covered  by :

Cindy  =  2 yards, 1 foot 3 inches = 3 ft x (2)  + 1 ft +  3 in  = 7 ft 3 in

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Nina   =   2 yards, 1 foot, 1 inch  = = 3 ft x (2)  + 1 ft +  1 in  = 7 ft 1 in

Monique   = 7 feet, 4 inches

So by comparing all distances, we can see that:

The maximum distances jumped by all four  is 7 ft 4 inches.

The distance covered by Drew is less than 7 ft 7 in.

So, he must have jumped 7 ft 5 inches OR 7 ft  6 inches.

Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft  6 inches.

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