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77julia77 [94]
3 years ago
5

1 + 2k = 5k + 7 I got k=2 don't know if it's the right answer ?

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
You are close, but it is not the correct answer.

1 + 2k = 5k + 7

First, since we are trying to get the variable by itself, we need to move all things to one side. Let's subtract 1 from each side. 
2k = 5k + 7 - 1

Second, we can now subtract (7 - 1) to get 6. Let's add that into our problem and then subtract 5 from each side, still trying to get the variable by itself.
2k - 5k = 6

Third, subtract (2k - 5k) to get -3k. Hint the negative symbol now. If the problem were switched the other way, it would still be a positive. 
-3k = 6

Fourth, we can now divide each side by -3. This results in a fraction and also getting the variable by itself on one side of the problem. Remember the negative sign in front of the fraction since (-3) carried it.
k = - \frac{6}{3}

Fifth, this is our last step. We need to simplify the fraction. Since out fraction is 6/3, which number multiples by 3 to get the answer of 6? The answer is 2, since (3 × 2 = 6). Don't forget the negative!
k = -2

Answer: \fbox {k = -2}
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NEED SOME HELP HERE!!
Stolb23 [73]

Answer:

6 and 8

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

Given this,

(3x)² + (4x)² = 10²

9x² + 16x² = 100

25x² = 100

Divide both sides by 25

x² = 4

x = 2

Substitute this into 3x and 4x.

3x = 3 * 2 = 6

4x = 4 * 2 = 8

Thus, the answer is 6 and 8

5 0
2 years ago
Feliz is looking at a cyclic quadrilateral EFGH. He says, "I'm not convinced that opposite
azamat

If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.

<h3>How to find angles of cyclic quadrilateral?</h3>

A cyclic quadrilateral is inscribed in a circle. It has all its vertices on the circumference of the circle.

Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.

Therefore,

∠F + ∠H = 180°

∠G + ∠E = 180°

Hence, if we moved ∠G to a different spot on the circle, angle FGH would change but angle FEH will also change to make the two opposite angles supplementary.

Therefore, Felix was wrong.

learn more on cyclic quadrilateral here: brainly.com/question/21208662

#SPJ1

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