4. A section of DNA that codes for a specific trait.
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
Answer: D. Digestion increases as the volume of the enzyme increases.
Explanation:
Enzymes speed up reactions by reducing the activation time of a reaction. If there are more enzymes therefore, the reaction will move faster.
Pepsin is an enzyme that prefers acidic conditions so it can work with dilute HCL. It can also work in temperatures of 40 °C without getting denatured. As more Pepsin is added therefore, the reaction will move faster and digestion will increase.
Answer:
The correct answer is "a hypertonic solution".
Explanation:
Seawater is the most clear example of a hypertonic solution in nature. The concentration of ions in seawater are far more superior than the concentration of ions inside a plant or an animal cell, since seawater have an osmolarity of about 1000 mOsm/l. Therefore, at high tide a plant or animal cell will be in a hypertonic solution, and the cells must have adaptions to avoid cell shrinking and dead.
Answer:
Both aerobic and anaerobic respiration.
Explanation:
Glycolysis may be defined as the process of break down of glucose molecules for the formation pf ATP with the help of enzymes and chemical factors. Glycolysis occurs in the cytosol of the organism.
Glycolysis may occur in the presence of organism known as aerobic respiration. The glycolysis can occur in the absence of oxygen as well known as anaerobic respiration. The steps involved up to the formation of pyruvate molecule from the glucose is same in case of aerobic and anaerobic respiration.
Thus, the correct answer is option (c).
