If f(X)= 7x +5/3 - x =6x +5/3
y= 6x +5/3
6x= y-5/3
f^-1(y)=x=(y-5/3)/6
So we can write
f(f^-1(y))= f((y-5/3)/6) = 6 (y-5/3)/6 +5/3= y-5/3+5/3= y
The same result can be obtained for f^-1(f(x))=x
If the function is f(x)= 7x +5/(3-x) then it is not invertible since it is not injective (pictures)
Answer:
The set of polynomial is linearly independent
Explanations:
For clarity and easiness of expression, the complete solution is handwritten in the file attached. However, the following are the steps taken:
1) The coordinate vectors of the polynomials are formed as:
(1,0,6,-1), (0,1,02) and (1,1,6,0)
2) A matrix is formed using the coordinates of the polynomials as the columns of the matrix
3) The polynomial formed is row reduced to form an echelon matrix.
4) As seen from the reduced echelon form of the matrix, the rank of the matrix = 3
5) since the rank = number of polynomials = 3, the set of polynomials is linearly independent.
Answer:
The value of given expression is .
Step-by-step explanation:
Given information: n=7, x=2, p=1/2
The given expression is
It can be written as
Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.
Therefore the value of given expression is .