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tia_tia [17]
3 years ago
9

Hellp with theseeee pls !! Asappp

Mathematics
1 answer:
Llana [10]3 years ago
3 0

Answer:

a is 60 ft^3 and b is 45

Step-by-step explanation:

b is 45 because 60/4 is 15, which would mean that 4/4 is 60, and since it says 3/4, you subtract 15 from 60 to get 45.

a is 60 because volume equals length times width times height, the three measurements shown

(edit)

and when multiplied you get 60 altogether.

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3 4/5 + 5 3/8 Please help ASAP Please i need the anwser
Hatshy [7]

Answer:

9 7/40

Step-by-step explanation:

3 4/5 + 5 3/8

First we need to get a common denominator of 40

3 4/5 * 8/8 = 3 32/40

5 3/8 *5/5 = 5 15/40

Add the fractions together

3 32/40+ 5 15/40

8  47/40

Rewriting

8 + 40/40 + 7/40

8 + 1+ 7/40

9 7/40

4 0
3 years ago
if a quadratic equation can be factored and each factor contains only real numbers then there cannot be an imaginary solution? T
Hunter-Best [27]
The answer to this question is:

<span>If a quadratic equation can be factored and each factor contains only real numbers then there cannot be an imaginary solution?
</span>"True"

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6 0
3 years ago
Read 2 more answers
PLZ HURRY IM RUNNING OUT OF TIME!!
Sonja [21]

Answer:

C-69%

Step-by-step explanation:

36-11=25

25/36=.694~69%

8 0
3 years ago
Which choice is equivalent to the quotient shown here when x &gt; 0?​
kramer
The answer should be D.
The square root of two.
7 0
3 years ago
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dos aviones parten de una ciudad con direcciones S32°E y E57°N¿ cuál es el angulo que forma sus direcciones?​
Elan Coil [88]

Answer:

El ángulo formado entre las dos direcciones es aproximadamente 115º.

Step-by-step explanation:

Las direcciones dadas en el enunciado significan lo siguiente:

S32ºE - <em>32º al este del sur.</em>

E57ºN - <em>57º al norte del este.</em>

Vectorialmente hablando, cada dirección es la siguiente:

S32ºE

A(x,y) = (\sin 32^{\circ}, -\cos 32^{\circ})

A(x,y) = (0.530, -0.848)

E57ºN

B(x,y) = (\cos 57^{\circ},\sin 57^{\circ})

B(x,y) = (0.545, 0.839)

El ángulo formado entre los dos vectores unitarios (\theta), medido en grado sexagesimales, puede determinarse mediante la siguiente ecuación vectorial:

\theta = \cos^{-1} \frac{A\,\bullet \,B}{\|A\|\cdot \|B\|}

Donde:

\|A\| - Norma de A(x,y).

\|B\| - Norma de B(x,y).

Si sabemos que A(x,y) = (0.530, -0.848), B(x,y) = (0.545, 0.839), \|A\| = 1 y \|B\| = 1, entonces el ángulo formado entre los dos vectores es:

\theta = \cos^{-1} \frac{(0.530)\cdot (0.545)+(-0.848)\cdot (0.839)}{(1)\cdot (1)}

\theta \approx 115^{\circ}

El ángulo formado entre las dos direcciones es aproximadamente 115º.

4 0
3 years ago
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