Step-by-step explanation:
4^m * 4^2 = 12
4^(m + 2) = 4^(log4 12)
m + 2 = log4 (12)
m = log4 (12) - 2.
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Hello!
The number line progresses from negative infinity (extreme left) to positive infinity (extreme right). Beginning at zero, the numbers increase in value as they move to the right and decrease in value as they move to the left.
With this knowledge, we can look at the number 17.2 (a positive number) and conclude that it is placed 17.2 units to the right of zero on the number line.
The opposite of 17.2 would be (-17.2). Again, looking at this number (a negative number), we can conclude that it is placed 17.2 units to the left of zero on the number line.
I hope this helps!
(5,0) if it’s asking the solution or do you want the equation? Technically the solution would be where the parabola touched the x axis
