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Rudiy27
3 years ago
9

A poster is shown below: A rectangle is shown. The length of the rectangle is labeled 10 feet. The width of the rectangle is lab

eled 4 feet. What are the dimensions if the poster is enlarged by a factor of three over two ? 12 ft by 30 ft 2 ft by 5 ft 6 ft by 15 ft 5 ft by 12 ft
Mathematics
2 answers:
makkiz [27]3 years ago
6 0
The enlarged length is (3/2)*10 ft = 15 ft.
The enlarged width is (3/2)*4 ft = 6 ft.

The dimensions of the enlarged poster are ...
  <span>6 ft by 15 ft</span>
lesya [120]3 years ago
5 0

Answer:

The dimensions of the enlarged poster are 6\ ft  by  15\ ft

Step-by-step explanation:

we know that

The scale factor is equal to the measure of the corresponding side of the enlarged poster divide by the the measure of the corresponding side of the original poster

Let

z-----> scale factor

x------> the measure of the corresponding side of the enlarged poster

y------> the measure of the corresponding side of the original poster

so

z=\frac{x}{y}

In this problem we have

z=\frac{3}{2}=1.5

Step 1

Find the length of the enlarged poster

x=zy

we have

z=1.5

y=10\ ft

substitute

x=1.5(10)=15\ ft

Step 2

Find the width of the enlarged poster

x=zy

we have

z=1.5

y=4\ ft

substitute

x=1.5(4)=6\ ft

therefore

the dimensions of the enlarged poster are 6\ ft  by  15\ ft



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liberstina [14]

Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0
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Ahat [919]

Answer:

They should sell 20 band posters.

Step-by-step explanation:

24 is 1/5 of 120 so we must find what 1/5 of 100 is.

it is 20.

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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7. Find the measure of the angle of elevation of the sun when a boy 5 feet tall cast's a shadow
Alecsey [184]

Answer:

45\degree

Step-by-step explanation:

We use trigonometry to find the angle of elevation.

From the diagram, the angle of elevation of the sun is \angle A

Recall the mnemonics SOH CAH TOA.

\tan A=\frac{Opposite}{Adjacent}

\tan A=\frac{5}{5}

\tan A=1

A=\tan^-1{1}=45\degree

Therefore the angle of elevation of the sun is 45\degree

See attachment

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Answer:

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2x+4x=16-10

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therefore, x is equal to 1

7 0
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