Answer:
I would answer but I cannot see it sorry :D
Step-by-step explanation:
Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
Answer:
14
Step-by-step explanation:
put -2 where x is
f(x)=-x^2-9x
f(-2)= -(-2)^2 -9(-2)
f(-2)= -4 + 18
f(-2)= 14
Rate of Change represents the number of apartments cleaned each hour & this is linear.
Answer:
This means the cost of the item to you is $57.75. You will pay $57.75 for a item with original price of $82.50 when discounted 30%. In this example, if you buy an item at $82.50 with 30% discount, you will pay 82.50 - 24.75 = 57.75 dollars.
