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2 years ago

Is a lamp bigger than a mug?

Mathematics

2 answers:

givi [52]2 years ago

8 0

Answer:

Whether you have your hot drinks in a ceramic or glass mugs, the difference is ... light kind of weight over the mugs when compared to the ceramic cup. ... can retain the heat for a much longer time duration than the glass cup.

Step-by-step explanation:

Hope this answer helps you :)

Have a great day

Mark brainliest

kolbaska11 [484]2 years ago

7 0

yes of course it's bigger, put a mug next to a lamp and there you will see it

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wlad13 [49]

Answer:

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Step-by-step explanation:

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2 years ago

A wire is attached to the top of a tower that is 100 feet tall. The wire is attached to the ground 40 feet of the tower What is

m_a_m_a [10]

Answer:

5/2

Step-by-step explanation:

i hope this is the answer

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2 years ago

Paul is running Tennis shop. He sells balls and rackets. Rackets (R) cost $1.20 each and Balls (B) cost $2:0 each. At the end of

Rus_ich [418]

The system of equations that represent the situation are 1.20R + 2B = 70, and R + B = 90.

<h3>What are the system of equations?</h3>

The system of equations are sets of equations that have to be solved simultaneously in order to determine their required values. They are often referred to as simultaneous equations.

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1 year ago

Which relationship has a zero slope?

Mandarinka [93]

Answer: X=0

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2 years ago

Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, start text, space, c, m, end text. He wan

mote1985 [20]

Answer:

<h2>The required ratio is 8</h2>

Step-by-step explanation:

Volume of a sphere = $\frac{4}{3}\pi r^{3}$ where r is the radius of the sphere.

If manuel bought a balloon (that is a perfect sphere) with a radius of 2cm, the original volume of the sphere is expressed as;

Vo = $\frac{4}{3}\pi (2)^{3}$

$Vo = \frac{4}{3}\pi *8\\Vo = \frac{32 \pi}{3}$

If he wanted his balloon to be bigger and he blew 2 big breaths of air into the balloon, if each big breath increased the balloon's radius by 1cm, the total radius will be the initial radius of the sphere plus the new radius after expansion.

radius of current sphere = 2cm+(1cm+1cm) = 4cm

Volume of the current sphere Vc = $\frac{4}{3}\pi (4)^{3}$

$Vc = \frac{4}{3}\pi *64\\Vc = \frac{256 \pi}{3} \\$

The ratio of the current volume of the balloon Vc to the original volume of the balloon Vo will be expressed as;

Vc/Vo = $\frac{\frac{256\pi}{3} }{\frac{32\pi}{3} }$

$\frac{Vc}{Vo}=\frac{256\pi}{3}*\frac{3}{32\pi} \\\frac{Vc}{Vo}=\frac{256}{32}\\\frac{Vc}{Vo}= 8$

The required ratio is 8

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2 years ago