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scZoUnD [109]
3 years ago
12

Plz help me with this

Mathematics
1 answer:
jeyben [28]3 years ago
7 0
10/15 =6/9

6*15=90
90/9=10, this is how I found 10,
also, is you simplify both, you get 2/3
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What’s he answer to this
nadezda [96]

The answer is two. This is because to find the volume of the figure, you need to multiple the length, width, and height of the figure. After doing so, you get 462. When you divide this by 231, you get 2.

4 0
4 years ago
A rectangular yard measuring 26 ft by 36 ft is bordered (and surrounded) by a fence. Inside, a walk that is 2 ft wide goes all t
cestrela7 [59]

Answer:

  232 square feet

Step-by-step explanation:

The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...

  yard including walk = (26 ft)(36 ft) = 936 ft²

The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...

  yard not including walk = (22 ft)(32 ft) = 704 ft²

The difference in these areas is the area of the walkway:

  walkway area = (yard including walk) - (yard not including walk)

  = (936 -704) ft² = 232 ft² . . . . area of the walk

_____

Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...

  (116 ft)(2 ft) = 232 ft²

4 0
3 years ago
An inconsistent independent system of equations is a system with
Dominik [7]

Answer:

intersecting lines that have the same slope but different y-intercepts

Step-by-step explanation:

I'm assuming this is from A P  E X , right?

5 0
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Helpppppppppppppppppppppp meeeeeeeeeeeeeee
il63 [147K]

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please give me brainLYEST I really need it please give me I beg you

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3 years ago
Find the Derivative y’ implicitly.
Brums [2.3K]

e^{x^2y} - e^y = e^y(e^{x^2} - 1) = x

<em>We should ISOLATE x</em>

<em />e^y= \frac{x}{e^{x^2} - 1}

<em>Find the Natural Log of Both Sides to Make the Left Side "y"</em>

<em />y = ln(\frac{x}{e^{x^2}-1})

<em>Now, FIND THE DERIVATIVE Using Chain Rule!!!</em>

<em />y' = \frac{1}{\frac{x}{e^{x^2}-1}} * \frac{(1(e^{x^2}-1) - x(2x*e^{x^2})}{(e^{x^2}-1)^2}= {\frac{e^{x^2}-1}{x}}* \frac{(1(e^{x^2}-1) - x(2x*e^{x^2})}{(e^{x^2}-1)^2} = {\frac{1}{x}}* \frac{(1(e^{x^2}-1) - x(2x*e^{x^2})}{(e^{x^2}-1)} =  {\frac{1}{x}}* \frac{(e^{x^2}-1 - 2x^2e^{x^2})}{(e^{x^2}-1)}

3 0
3 years ago
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