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3 years ago

ASAPPPPPPPPP

Mathematics

2 answers:

maxonik [38]3 years ago

8 0

Answer:the answer is C. I pray for you all I hope you graduate!

Step-by-step explanation:

Neporo4naja [7]3 years ago

3 0

Answer:

The answer is D

3(x+4)(x-i)(x+i)(x-2)

Step-by-step explanation:

You might be interested in

Simplify (3х2 – 2) + (2х2 – бх + 3).

kolbaska11 [484]

Answer:

5x^2 -6x +1

Step-by-step explanation:

(3х^2 – 2) + (2х^2 – бх + 3).

Combine like terms

(3х^2 + 2х^2 – бх + 3-2)

5x^2 -6x +1

4 0

3 years ago

Arizbeth spent $20.08 to put 8 gallons of gas in her car. How much would 13 gallons have cost?

Misha Larkins [42]

Answer:

32.63

Step-by-step explanation:

since arizbeth is spending $20.08 to put 8 gallons in her car the first step is to divide 20.08 by 8.Then since you have per gallon you have to figure out what 13 gallons is so you multiply per gallon by 13

8 0

3 years ago

Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

5 0

3 years ago

Find the equation of this line. y= [?]x+[?]

DochEvi [55]

Answer:

$y=3x-4$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x=0)

1) Determine the slope (m)

$m=\displaystyle\frac{y_2-y_1}{x_2-x_1}$ where two points that fall on the line are $(x_1,y_1)$ and $(x_2,y_2)$

On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:

$m=\displaystyle\frac{2-(-4)}{2-0}\\\\m=\displaystyle\frac{2+4}{2}\\\\m=\displaystyle\frac{6}{2}\\\\m=3$

Therefore, the slope of the line is 3. Plug this into $y=mx+b$ :

$y=3x+b$

2) Determine the y-intercept (b)

$y=3x+b$

Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into $y=3x+b$ :

$y=3x+(-4)\\y=3x-4$

I hope this helps!

5 0

3 years ago

Given that ∠A≅∠B, Evelia conjectured that ∠A and ∠B are acute angles.

Valentin [98]

Answer:

answer is choice 4 because in te given angle A and angle B are congrunt and if they are acute the degree measure is 0-90

6 0

3 years ago