The answer to your question would be -10
Answer:
d
Step-by-step explanation:
You need to find a common factor that both the
numerator
and denominator have. 16 and 12 have common divisible factors of 2 and 4(excluding 1, because 1 is self-defined but doesn't simplify values at all).
We use the highest factor, in this case, 4.
Divide 16 by 4 and 12 by 4.
16/4 = 4
12/4 = 3
We put 4 in place of the numerator and 3 in place of the denominator.
Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
It would be -4x+(-12)=12 good luck