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sertanlavr [38]
2 years ago
8

What is the median for 9, 37, 39, 13

Mathematics
2 answers:
8090 [49]2 years ago
6 0

Answer:

i'm not sure

Step-by-step explanation:

Anna35 [415]2 years ago
6 0

Answer:

(13+37)/2 = 25

Step-by-step explanation:

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The number 1,645.6 expressed in scientific notation equals
grin007 [14]

Answer:

1.6456 * 10^{3}

Step-by-step explanation:

<u>Step 1:  Convert to Scientific Notation</u>

<u />1645.6 is in standard notation

1.6456 * 10^{3} is in scientific notation

Answer:  1.6456 * 10^{3}

8 0
3 years ago
Which number is the BASE?<br> 23=8<br> 8
ICE Princess25 [194]

Answer:

Step-by-step explanation:

For example, the base-8 numeral 23-8 contains two digits, "2" and "3", and with a base number (subscripted) "8". When converted to base-10, the 23-8 is equivalent to 19-10, i.e. 23-8 = 19-10.

3 0
3 years ago
the graph of a line has a slope of -2/3 and a y intercept of (0,2). rewrite the equation in standard for (Ax+By=C) with a positi
sergiy2304 [10]

Answer:

2x + 3y = 6

Step-by-step explanation:

obtain the equation in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

here m = - \frac{2}{3} and c = 2

y = - \frac{2}{3} x + 2 ← in slope-intercept form

multiply all terms by 3 to eliminate the fraction

3y = - 2x + 6 ( add 2x to both sides )

2x + 3y = 6 ← in standard form


8 0
3 years ago
i promise i will mark brainliest if the point (-3,4) is the vertex point of the curve of aquadratic function f and -5 is aroot o
Jet001 [13]

Ans:

(x+5)(x+1)+8

Step by step explanation:

-5 was mentioned as the 0 of the first root: (x+5). Then with some maneuvering we can plot (-3,4) then add (x+1) because they land on the same y axis. then we add 8 to get it right on the vertex.

6 0
3 years ago
How many ways can u write 5 to the power of 8 as a quotient of two exponential terms?
skad [1K]
Hello,

The answer is "4 ways".

Reason:

You can write it these ways:

= 5^12 / 5^4
= 5^9 / 5
= 5^10 / 5^2
<span>= 5^15 / 5^ 7

Therefore you can write it 4 different ways....

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit</span>
5 0
3 years ago
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