Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Answer:
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Step-by-step explanation:
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Answer:
The answer is C 66%
Step-by-step explanation:
Replace x with x+3:
f(x+3) = (x+3)²
which is x² translated 3 units left
Answer:
44 mph
Step-by-step explanation:
Given that:
Before lunch :
Time taken = 2hrs ; at speed = x mph
After lunch :
Time taken = 3hrs ; at speed = x + 10 mph
Total distance covered = 250 miles :
Distance = speed * time
(2 * x) + (3 * (x + 10)) = 250
2x + 3x + 30 = 250
5x + 30 = 250
5x = 250 - 30
5x = 220
x = 220/ 5
x = 44 mph
Rate before lunch is 44mph
