3 years ago

1.1. The factors of 64a3 + 343b3 are

Mathematics

1 answer:

laiz [17]3 years ago

3 0

Answer:

(4a + 7b)(16a² - 28ab + 49b²)

Step-by-step explanation:

Use the sum of two cubes to factor

In addition

a³ + b³ = (a + b)(a² - ab + b²)

In subtraction

a³ - b³ = (a - b)(a² + ab + b²)

64a³ + 343b³ = (4a + 7b)(16a² - 28ab + 49b²)

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1.1. The factors of 64a3 + 343b3 are​

1.1. The factors of 64a3 + 343b3 are