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jeka57 [31]
3 years ago
13

Randomly picking a white card from a bag containing all red cards

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0
What is it ??????????????
ra1l [238]3 years ago
3 0
What are the chances?
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The image of the point (-8, 3) under a translation is (-5,2). Find the coordinates
miss Akunina [59]

Answer:

IMAGE=OBJECT +TRANSLATION

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3 years ago
First-order linear differential equations
kkurt [141]

Answer:

(1)\ logy\ =\ -sint\ +\ c

(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Step-by-step explanation:

1. Given differential equation is

  \dfrac{dy}{dt}+ycost = 0

=>\ \dfrac{dy}{dt}\ =\ -ycost

=>\ \dfrac{dy}{y}\ =\ -cost dt

On integrating both sides, we will have

  \int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}

=>\ logy\ =\ -sint\ +\ c

Hence, the solution of given differential equation can be given by

logy\ =\ -sint\ +\ c.

2. Given differential equation,

    \dfrac{dy}{dt}\ -\ 2ty\ =\ t

=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty

=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})

=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt

On integrating both sides, we will have

   \int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}

=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c

=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Hence, the solution of given differential equation is

log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

8 0
3 years ago
What is the value of the 8th term of the sequence 4, 8, 16, 32, ...?
vladimir1956 [14]

Answer:

512

Step-by-step explanation:

The sequence is doing the number times 2, so 4 times 2 equals 8,

8 x 2 = 16, ect

If you do this enough, you will get 512 as the 8th term.

3 0
2 years ago
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the length of a varies string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a
kolbaska11 [484]

Answer: <u><em>512</em></u>

Step-by-step explanation: <u><em>the length of a varies string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a frequency of 512 cycles per second. Find the frequency of an 8-inch string.​</em></u>

<u><em /></u>

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A good friend of yours
KATRIN_1 [288]
Sorry i have learnt it but i can remember how to do it

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