Answer:
1. (-4,6) there is no a solution to the equation through this point
2. (2,−6) there is no a solution to the equation through this point
3. (−5,39) there is a solution to the equation through this point
4. (−1,45) there is a solution to the equation through this point
Step-by-step explanation:
Using the existence and uniqueness theorem:
Let:

Now, let's find the domain of
, due to the square root:

So the domain of the function is:

Now, due to the fraction
the denominator must be also different from 0, so:

So, the theorem tells us that for each
there exists a unique solution defined in an open interval around
.
1. (-4,6) there is no a solution to the equation through this point because 
2. (2,−6) there is no a solution to the equation through this point because

3. (−5,39) there is a solution to the equation through this point because

4. (−1,45) there is a solution to the equation through this point because
