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3 years ago

What is the ratio of rise to run between the points (0, 4) and (5, 6)? A.5/2 B.-5/2 C.2/5 D.-2/5

Mathematics

2 answers:

IRISSAK [1]3 years ago

4 0

Answer:

D.25

Step-by-step explanation:

RUDIKE [14]3 years ago

3 0

Answer:

http://mansfieldalgebra1.weebly.com/uploads/1/0/4/4/10447339/rc_2_answer_key.pdf

Step-by-step explanation:

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Pls answer both help asap

icang [17]

Answer:

c .both..............

6 0

3 years ago

You need to cross a canal and want to determine the distance across the opposite side. Since you're able to take measurements on

MariettaO [177]

Answer:

36.7 ft

Step-by-step explanation:

Measurements for the sides of the canal is given as: 40 ft. and 16 ft.

You solve the above question using Pythagoras Theorem

The distance across the canal is calculated as:

√(40² - 16²)

= √(1344)

= 36.66060556 ft

Approximately = 36.7 ft

Therefore, the distance x across the canal = 36.7 ft

8 0

3 years ago

1/2 (6x-10) - x =<br><br> What's the other side of the equation?

LiRa [457]

Answer:

Step-by-step explanation:

1/2 (6x-10) - x

Opening bracket

= 6x/2 - 10/2 - x

= 3x - 5 - x

= 2x - 5

4 0

3 years ago

SOLUTION: y = 5x + 7 what is the value of y

Nat2105 [25]

There are an infinite number of solutions given the information you provided. For every real value of x there will be a corresponding real value of y.

y=5x+7 Has not restriction upon the domain or range...

What is the value of y? 5x+7

8 0

3 years ago

Read 2 more answers

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

3 years ago