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lukranit [14]
3 years ago
12

REMAX, a real estate company in Houston, performed an analysis of 500 Houston homes they sold last year. Each home was categoriz

ed by initial asking price and number of days the home was listed before it sold. Reference Equations Number of Homes: Initial Asking Priceless or equal than$200,000 Initial Asking Price> $200,000 Total Days Listed Until Sold less or equal than30 125 95 220 Days Listed Until Sold >30 115 165 280 Total 240 260 500 Find P(price > $200,000 and sold less or equal than 30 days). a. 0.3654 b. 0.1900 c. 0.2288 d. 0.4318
Business
1 answer:
Ilya [14]3 years ago
5 0

Answer: 0.1900

Explanation:

To find P(price > $200,000 and sold less or equal than 30 days), we have to look at the reference equation table and then look out for the point whereby price is greater than $200000 and sold less or equal than 30 days.

Based on the information given, this will be at a point where we've 95. Since the overall possible outcome is 500, then P(price > $200,000 and sold less or equal than 30 days) will be:

= 95/500

= 0.1900

The correct option is B.

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Pega if report is created in myco-hr-selfservice-work, what instances will the report return?
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Since a subclass can inherit the variables or methods of the superclass, the instances which the report will return is: B. MyCo-HR-SelfService-Work-TimeOff and MyCo-HR-SelfService-Work-Expense.

<h3>What is a class?</h3>

A class can be defined as a user-defined blueprint (prototype) or template that is typically used by software programmers to create objects and define the data types, categories, and methods that should be associated with these objects.

In object-oriented programming (OOP) language, an object class represents the superclass of every other classes when using a programming language such as Java. Also, the superclass is more or less like a general class in an inheritance hierarchy.

Since a subclass can inherit the variables or methods of the superclass, the instances which the report will return is "MyCo-HR-SelfService-Work-TimeOff and MyCo-HR-SelfService-Work-Expense" because they are declared within the class group.

Read more on object class here: brainly.com/question/27999316

#SPJ1

Complete Question:

Consider the following Work-derived classes that belong to the same class group:

MyCo-HR-SelfService-Work

MyCo-HR-SelfService-Work-TimeOff

MyCo-HR-SelfService-Work-Expense

There are no instances of MyCo-HR-SelfService-Work.

If a report is created in MyCo-HR-SelfService-Work, what instances will the report return?

Group of answer choices.

A. MyCo-HR-SelfService-Work-TimeOff and MyCo-HR-SelfService-Work-Expense, only if the "Report on Descendant Class Instances" checkbox is selected

B. MyCo-HR-SelfService-Work-TimeOff and MyCo-HR-SelfService-Work-Expense

C. No records

D. Instances of all Work- derived classes

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2 years ago
Shay is preparing to go into her meeting with her supervisor, Jill, to discuss her annual evaluation. She knows that there have
ehidna [41]

Shay was trying to: resist being defensive.

<h3><u>Explanation:</u></h3>

The term resist refers to the act of withstanding. It is an act through which a person fights firmly and strongly. The act through which an individual induces threats through the behaviour refers to be defensive. It makes them to be unique in the task they do. A person will be resist and defensive when he or she knows that their work is good enough and there will be no pint to prove them wrong or blamed.

In the given scenario, Shay knows that she performed better and he prepares herself not to be angry in the meeting held by her supervisor. She prepares herself with the entire question that will be asked her by the supervisor and how she must react to those questions. Thus, Shay was trying to: resist being defensive.

5 0
3 years ago
Fifteen married couples are at a dance lesson, but now only five men and five women are selected at random, then randomly paired
Tresset [83]

Answer:

( ¹⁵C₂ )² × 5! = 1082161080

Explanation:

Data provided in the question:

Number of married couples = 15

Therefore,

Number of males = 15

Number of females = 15

Now,

The number of possible dancing arrangements

= Probability of selecting males × Probability of selecting males × ways of arranging 5 pairs

= ¹⁵C₂ × ¹⁵C₂ × 5!

= ( ¹⁵C₂ )² × 5!

= [\frac{15!}{5!\times(15-5)!}]^2 × ( 5 × 4 × 3 × 2 × 1 )

= [\frac{15\times14\times13\times12\times11\times10!}{5\times4\times3\times2\times1\times10!}]^2 × ( 5 × 4 × 3 × 2 × 1 )

= [\frac{360360}{120}]^2 × 120

= 1082161080

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