Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
0.72
- .20
------------
0.52 (.20 is two tenths)
Answer:
x = - 
Step-by-step explanation:
(x - 3) - 5 =
(x - 1)
Multiply through by 8 to clear the fractions
6(x - 3) - 40 = x - 1 ← distribute parenthesis and simplify left side
6x - 18 - 40 = x - 1
6x - 58 = x - 1 ( subtract x from both sides )
5x - 58 = - 1 ( add 58 to both sides )
5x = - 57 ( divide both sides by 5 )
x = - 
Answer: $1,135.15
Step-by-step explanation:
First calculate his basic pay;
= 40 * 14.60
= $584
Total for overtime worked during the week;
= 15 * 14.60 * 1.25
= $273.75
Total for overtime worked on Saturday;
= 6 * 14.60 * 1.5
= $131.40
Total for overtime worked on Sunday;
= 5 * 14.60 * 2
= $146
Sum all the figures;
= 584 + 273.75 + 131.40 + 146
= $1,135.15
Is it multiple choice or do you have to write a answer?