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LenaWriter [7]
3 years ago
11

The tendency to perceive a series of points or lines as having unity is the Gestalt rule of organization known as ________.

Physics
2 answers:
xxMikexx [17]3 years ago
5 0
The best answer to fill in the blank should be ''continuation'' because series means a lot and lines are long, narrow, figures, so its continuation since its constant.
levacccp [35]3 years ago
3 0

Answer:

The tendency to perceive a series of points or lines as having unity is the Gestalt rule of organization known as <u>Continuity</u>.                                            

Explanation:

The Gestalt school of psychology which was founded in the 20th century provided the foundation for the modern study of perception. the Gesalt theory emphasizes that the whole of anything is greater than its parts. That is, the attributes of the whole are not deducible from analysis of the parts in isolation.

 

With respect to sensation and perception, there are several rules which have been identified. They are

  1. The rule of Symmetry
  2. The rule of Similarity
  3. The rule of Proximity
  4. The rule of Common Fate and
  5. The rule of Continuity.

Another way to state the law of continuity is to say that once the eye begins to follow something, it will continue traveling in that direction until it encounters another object. A good example is a line with an arrow at the end of it.

Cheers!

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Answer:

A shorter than the original source and in the researcher's words

Explanation:

The summary is an abridged version of the original source and in the researcher's own very words.

Summaries gives an over-arching perspective and excludes implicit details from a given text.

A summary should not be detailed and must avoid overt illustrations. They must capture the true essence of piece leaving out flowery details.

A summary should be lesser in length than the original piece. Any third party reader should immediately be able to grab the details of the original piece from the summary.

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A string is wrapped around a pulley with a radius of 2.0 cm and no appreciable friction in its axle. The pulley is initially not
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Explanation:

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Light with an intensity of 1 kW/m2 falls normally on a surface and is completely absorbed. The radiation pressure is
kobusy [5.1K]

Answer:

The radiation pressure of the light is 3.33 x 10⁻⁶ Pa.

Explanation:

Given;

intensity of light, I = 1 kW/m²

The radiation pressure of light is given as;

Radiation \ Pressure = \frac{Flux \ density}{Speed \ of \ light}

I kW = 1000 J/s

The energy flux density = 1000 J/m².s

The speed of light = 3 x 10⁸ m/s

Thus, the radiation pressure of the light is calculated as;

Radiation \ pressure = \frac{1000}{3*10^{8}} \\\\Radiation \ pressure =3.33*10^{-6} \ Pa

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What was the direction of the ball’s velocity
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Part of the question is missing. Here it is:

<em>A 72 g autographed baseball slides off of a 1.3 m high table and strikes the floor a horizontal distance of 0.7m away from the table.     The acceleration of gravity is 9.81 m/s2. What was the direction of the ball’s velocity  just before it hit the floor? </em>

Answer:

\theta=-75.7^{\circ}

Explanation:

The motion of the ball is a projectile motion, which consists of two separate motions:

- A horizontal motion at constant velocity

- A vertical motion at constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time of flight of the ball. This can be done by using the suvat equation

s=ut+\frac{1}{2}at^2

where, choosing downward as positive direction:

s =1.3 m is the vertical displacement of the ball

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time

Solving for t,

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(1.3)}{9.8}}=0.52 s

Now we can find the final vertical velocity of the ball, using:

v_y=u+at

And susbtituting t = 0.52 s, we find

v_y = 0 +(9.8)(0.52)=5.1 m/s

It is important to keep in mind that the direction of this velocity is downward, since we chose downward as positive direction.

The horizontal velocity of the ball instead is constant; we know that the ball covers a horizontal distance of

d = 0.7 m

In a time of

t = 0.52 s

So, the horizontal velocity is

v_x = \frac{0.7}{0.52}=1.3 m/s

So now we can find the direction of the ball's velocity using:

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{5.1}{1.3})=75.7^{\circ}

And since the vertical direction is downward, this means that this velocity is below the horizontal, so the answer is

\theta=-75.7^{\circ}

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