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gregori [183]
3 years ago
10

A car traveled 60km in 45 min.What is the cars average speed in km/hr

Physics
1 answer:
sergey [27]3 years ago
5 0

Given that,

Distance = 60 km

Time = 45 min

To find,

The average speed of the car.

Solution,

Average speed of an object is equal to the total distance divided by total time taken.

45 min = 0.75 hour

It can be given as :

V=\dfrac{60\ km}{0.75\ h}\\\\=80\ km/h

Therefore, the average speed of the car is 80 km/hr.

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Lora (of mass 47.4 kg) is an expert skier. She
Harrizon [31]

Answer:

Kinetic energy is 242.7 Joule

Explanation:

m = 47.4 kg

v = 3.2m/s²

Now,

K.E. = 1/2 × m × v²

or, K.E. = 1/2 × 47.4 × 3.2²

or, K.E. = 242.7 Joule

6 0
3 years ago
An elevator weighs 1500 Newtons. Calculate how much potential energy it has when it is lived 500 meters in the air.
avanturin [10]

An elevator has 750,000 J when it is lived 500 meters in the air

Answer: Option D

<u>Explanation:</u>

The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as

potential\ energy (P . E)=m \times acceleration\ due\ to\ gravity\ (g) \times height (h)

Where,

m – mass of object

Acceleration due to gravity =  9.8 \mathrm{m} / \mathrm{s}^{2}

h = 500 meters

Force = 1500 Newton

As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as

P . E=F \times h=1500(500)=750000 J

Hence, an elevator has 750,000 J when it is lived 500 meters in the air.

4 0
3 years ago
Earth’s surface is subjected to unusually high rates of weathering. The Moon and some of the inner planets of our solar system a
Komok [63]
<h2>Answer:</h2>

<em><u>Running water on the Surface of Earth.</u></em>

<h2>Explanation:</h2>

Weathering can be defined as the phenomenon of breaking or disintegration of the rocks, minerals, soil etc. due to coming in contact with the Earth's atmosphere such as the Water, Wind, Organisms etc.

In this process the rocks, minerals disintegrate into lot of small particles.

But the rate of weathering on Earth is at a very unusual or unique rate because Earth's surface has the presence of the running water that leads to the high rate of surface weathering.

<em><u>Therefore, the reason of Earth's rapid weathering rates is Running water on the Surface of Earth.</u></em>

<em><u></u></em>

3 0
3 years ago
A shield of material that reflects neutrons is placed around a radioactive sample. Which change in the nuclear reaction is most
Crazy boy [7]

Answer:

A chain reaction will be sustained in a sub-critical mass.

Explanation:

Hope this helps!

If not, I am sorry.

3 0
2 years ago
A ball is launched at an angle of 10 degrees from a 20 meter tall building with a speed of 4 m/s. How long is the ball in the ai
shutvik [7]

Answer:

d) None of the above

Explanation:

v_{o} = inituial velocity of launch = 4 m/s

θ = angle of launch = 10 deg

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 20 m  

t = time of travel

using the equation

y=v_{oy} t+(0.5)a_{y} t^{2}

- 20 = (0.695) t + (0.5) (- 9.8) t²

t = 2.1 sec

consider the motion along the horizontal direction

x = horizontal displacement

v_{ox} = initial velocity along horizontal direction = 4 Cos10 = 3.94 m/s

a_{x} = acceleration along the horizontal direction = 0 m/s²

t = time of travel =  2.1 s

Using the kinematics equation

x =v_{ox} t+(0.5)a_{x} t^{2}

x = (3.94) (2.1) + (0.5) (0) (2.1)²

x = 8.3 m

Consider the motion along the vertical direction

v_{oy} = initial velocity along vertical direction = 4 Sin10 = 0.695

m/s

a_{y} = acceleration along the vertical direction = - 9.8 m/s²

y_{o} =initial vertical position at the time of launch = 20 m  

y = vertical position at the maximum height = 20 m

v_{fy} = final velocity along vertical direction at highest point = 0 m/s

using the equation

{v_{fy}}^{2}= {v_{oy}}^{2} + 2 a_{y}(y - y_{o})

0^{2}= 0.695^{2} + 2 (- 9.8)(y - 20)

y = 20.02 m

h = height above the starting height

h = y - y_{o}

h = 20.02 - 20

h = 0.02 m

7 0
3 years ago
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