Given:
Mean, μ = 196
Std. dev., σ = 22
A sample size of 50 (> 30) is large enough to provide meaningful data.
The random variable is x = 200.
The z-score is
z = (x - μ)/σ = (200 - 196)/22 = 0.1818
From normal distribution tables, obtain
Prob(X < 200) = 0.572 = 57.2%
Answer: 57.2%
sorry I don't know if I know I would surely say u
Title:
<h2>The revenue will be maximum for 253 passengers.</h2>
Step-by-step explanation:
Let, the number of passenger is x, which is more than 194.
In this case, the travel agency will charge [312 - (x - 194)] per passenger.
The total revenue will be ![x[312 - (x - 194)] = 506x - x^{2}](https://tex.z-dn.net/?f=x%5B312%20-%20%28x%20-%20194%29%5D%20%3D%20506x%20-%20x%5E%7B2%7D)
.
As x is the variable here, we can represent the revenue function by R(x). Hence, 
.
The revenue will be maximum when 
.
Answer:
Cost Price = Rs 10000
Step-by-step explanation:
Assume:
Cost of the item = x
Item was sold at a loss of 20%:
Loss = 20% of x = 0.2x
Item sold = x - 0.2x = 0.8x
Item sold at a profit of 10%:
Profit = 10% of x = 0.1x
item sold = x + 0.1x = 1.1x
Solve:
Difference = 1.1x - 0.8x = 0.3x
0.3x = Rs 3000
x = Rs 3000 ÷ 0.3
x = Rs 10000
Y = 2x + 12
2(4) + 12 = 8 + 12 = 20
She spends $20
